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3 years ago

DO NOT PUT IN A LINK JUST TELL ME this is serious this is a test(NOO LINK!!!!!!)

Mathematics

1 answer:

Svet_ta [14]3 years ago

7 0

Answer:

the answer is 4 because 16×4 is 64

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Is that better talbottislan

Alenkinab [10]

Answer:

Step-by-step explanation:

the most common #is 10

7 0

3 years ago

4. Solve the following system of equations for x.

Ber [7]

We are given the system of equations -:

$\large{ \begin{cases} 2x + 3y = - 14 \\ y = 6x + 22 \end{cases}}$

Since the second equation is y-isolated equation. It can be substituted as y = 6x+22 in the first equation.

$\large{2x + 3(6x + 22) = - 14}$

Expand 3 in the expression so we can combine like terms and isolate x-variable.

$\large{2x + 18x + 66 = - 14}$

Then combine like terms.

$\large{20x + 66 = - 14}$

Get rid of 66 from the left side by subtracting both sides by itself.

$\large{20x + 66 - 66 = - 14 - 66} \\ \large{20x = - 80}$

To finally isolate the variable, divide both sides by 20 so we can leave x only on the left side.

$\large{ \frac{20x}{20} = \frac{ - 80}{20} }$

Simplify to the simplest form.

$\large{x = - 4}$

Normally, we have to find the y-value too but since we only find x-value. The answer is x = -4.

Answer

x = -4

I hope this helps! If you have any questions or doubts regarding my answer, explanation or system of equations, feel free to ask!

5 0

3 years ago

A cube an edge length is 18in. What is it's volume?

Maksim231197 [3]

The answer would be 18*18*18=5832
Good luck ^-^

5 0

3 years ago

Use elimination to solve each system.

stiks02 [169]

Box of Popcorn: $3.00
Drink: $2.00

I might be wrong, but hopefully that helped! :)

5 0

3 years ago

The first term of a geometric sequence is equal to a and the common ratio of the sequence is r.

ololo11 [35]

Answer: (a) {a, ar, ar², ar³, ar⁴, ar⁵...}, (b) arⁿ⁻¹

For part (a), the question gives us the first term a, and then asks us to apply the common ratio r six times.

In order for ar = a, the nth term of r will have to equal 0 (this implies that n is an exponent; thus giving us the first term a, as r = 1).

Since we use this method on the first term, we must use it for the next five, in which r gains an additional exponent for every consecutive value (nth term) thereafter.

Ultimately getting: {a, ar, ar², ar³, ar⁴, ar⁵...}

For part (b), we first have to understand that the sequence does not start at 0, but at 1 for n. In order for ar = a, with n = 1, there needs to be subtraction of -1 within the exponent. So that arⁿ⁻¹

If we check and apply this, we can see that:

{ar¹⁻¹, ar²⁻¹, ar³⁻¹, ar⁴⁻¹, ar⁵⁻¹, ar⁶⁻¹...} = {a, ar, ar², ar³, ar⁴, ar⁵...} = arⁿ⁻¹ = Tn

4 0

3 years ago