Answer:
21.2 in.
Step-by-step explanation:
(4)(3.14)(1.3^2) = 21.2
Answer:
a) For this case we see that the cumulative % for 600 is 77.1% so then we will have 0.771 of the values below 600
b) For this case we know that the cumulative percent for 1200 is 98.2% so then the percentage above would be 100-98.2 = 1.8%, so then the proportion above 1200 would be 0.018.
c) For this case we can add the percentages obtained from the previous parts and we got : 77.1% +1.8% = 78.9% and then the proportion that are less than 600 and at least 100 would be 0.789
Step-by-step explanation:
Assuming the cumulative percentages in the figure attached.
What proportion of fire loads are less than 600?
For this case we see that the cumulative % for 600 is 77.1% so then we will have 0.771 of the values below 600
What proportion of fire loads are At least 1200?
For this case we know that the cumulative percent for 1200 is 98.2% so then the percentage above would be 100-98.2 = 1.8%, so then the proportion above 1200 would be 0.018.
What proportion of fire loads are less than 600 at least 120?
For this case we can add the percentages obtained from the previous parts and we got : 77.1% +1.8% = 78.9% and then the proportion that are less than 600 and at least 100 would be 0.789
Answer:
18 students for each teacher and 10 for each tutor, and if the academy had 80 students it would have 8 tutors
Step-by-step explanation:
Answer:
-40
Step-by-step explanation:
a. P(odd sum)
OK, each is drawing from a pile of 2 even cards and one odd, so have a 2/3 chance of picking even and a 1/3 chance of picking odd.
1/3 × 1/3 = 1/9 probability of odd+odd = even
1/3 × 2/3 = 2/9 prob of odd + even = odd
2/3 × 1/3 = 2/9 prob of even + odd = odd
2/3 × 2/3 = 4/9 prob of even+even = even
Total odd: 2/9+2/9 = 4/9
Answer: a) 4/9
b. P(sum < 11)
Let's just work out all the possibilities and count.
1st 2nd sum
4 4 8
4 5 9
4 6 10
5 4 9
5 5 10
5 6 11
6 4 10
6 5 11
6 6 12
I count 6 of 9 are less than 11, so P=6/9 or
Answer: b) 2/3