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2 years ago

1. The hypotenuse of a right triangle has a length of 10.0 and one of its

Mathematics

1 answer:

Mamont248 [21]2 years ago

7 0

Answer:

I wont tell you the answer but I can tell you how to solve this one.

Step-by-step explanation:

If they are both squared then square them. Once you have the hypotenuse and the leg squared subtract the leg from the hypotenuse. That's your answer. Then you un- square it by finding the square root of the new number. That square root is your answer

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bella types at a constant rate of 42 per minute. is the number of words she can type proportional to the number of minutes she t

Ksivusya [100]

Yes I think so because she write 42 per minute the question doesn't tell you anything else.
I am not sure :(

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2 years ago

How do i do this???????

Fittoniya [83]

Answer:

2y-4-6y-12=4

-4y=20

y= -5

Step-by-step explanation:

because (y+2)(y-2)=y^2-4

so we have the step to let the every part have the same denominator y^2-4

2(y-2)/(y+2)(y-2) -6(y+2)/(y-2)(y+2)=4/(y-2)(y+2)

the denominators are the same so the equality .we just need the part over be the same 2y-4-6y-12=4

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2 years ago

We're doing math practice what's the answer

cluponka [151]

Multiply 36 by 75 because they need to find how many yards they need

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2 years ago

Leslie and her family went out to dinner last night. The total bill was $78.44 after the 6% tax. How much was the bill before ta

sleet_krkn [62]

Answer:

$74

Step-by-step explanation:

you convert the percent to a decimal, .06, and try multiplying it with the numbers before 78, so you multiply it with 77, 76, 75, then 74, and when you multiply it with 74 you get 78.44.

Or you figure out the total amount money wise that the tax would count as and subtract that from 78.44.

5 0

2 years ago

In how many ways can you arrange 6 digits to make a 3-digit number without repeating a digit?

White raven [17]

The number of ways n different objects can be arranged, taking r objects at a time, without repeating any object is given by:

$^nP_r= \frac{n!}{(n-r)!}$

Given 6 different digits, the number of ways to arrange 6 different digits to make a 3 digit number without reapeating a digit is given by:

$^6P_3= \frac{6!}{(6-3)!} \\ \\ = \frac{6!}{3!} = \frac{6\times5\times4\times3!}{3!} \\ \\ =6\times5\times4=120$

Therefore, the number of <span>ways 6 digits can be arranged to make a 3-digit number without repeating a digit</span> is 120 ways.

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3 years ago