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tia_tia [17]
3 years ago
7

Please help and thank you

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
8 0

I'm honestly not really sure, but it has to be either (2,10) or (10,2). I've never seen a question like this...

Answer:

Step-by-step explanation:

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Classify each of the power functions based on their end behavior (increasing or decreasing) as x = ∞
Svetlanka [38]

Answer: right side behavior:

              f(x) is Decreasing

             g(x) is Increasing

             h(x) is Increasing

             j(x) is Decreasing

<u>Step-by-step explanation:</u>

The rules for end behavior are based on 2 criteria: Sign of leading coefficient and Degree of polynomial

<u>Sign of leading coefficient</u> (term with greatest exponent):

  • If sign is positive, then right side is increasing
  • If sign is negative, then right side is decreasing

<u>Degree of polynomial</u> (greatest exponent of polynomial:

  • If even, then end behavior is the same from the left and right
  • If odd, then end behavior is opposite from the left and right

f(x) = -2x²

  • Sign is negative so right side is decreasing
  • Degree is even so left side is the same as the right side (decreasing)

as x → +∞, f(x) → +∞  Decreasing

as x → -∞, f(x) → -∞   Decreasing

g(x) = (x + 2)³

  • Sign is positive so right side is increasing
  • Degree is odd so left side is opposite of the right side (decreasing)

as x → +∞, f(x) → +∞  Increasing

as x → -∞, f(x) → -∞   Decreasing

h(x)=-1+x^{\frac{1}{2}}\implies h(x)=x^{\frac{1}{2}}-1  

  • Sign is positive so right side is increasing
  • Degree is an even <u>fraction</u> so left side is opposite of the right side as it approaches the y-intercept (-1)

as x → +∞, f(x) → +∞  Increasing

as x → -∞, f(x) → -1    Decreasing to -1

j(x)=\dfrac{1}{2}(-x)^5\implies j(x)=\dfrac{1}{2}(-1)^5(x)^5\implies j(x)=-\dfrac{1}{2}x^5

  • Sign is negative so right side is decreasing
  • Degree is odd so left side is opposite of the right side (increasing)

as x → +∞, f(x) → +∞  Decreasing

as x → -∞, f(x) → -∞   Increasing

6 0
3 years ago
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