3 years ago

Please help I only have a few minutes left

Mathematics

1 answer:

GalinKa [24]3 years ago

6 0

Answer:

4 because that's where the lines intercept

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3 years ago

Rewrite the equation of the parabola in vertex form. y= x2 + 8x - 21

sergey [27]

Answer:

$y=(x+4)^{2}-37$

Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

$y=a(x-h)^{2}+k$

where

(h,k) is the vertex of the parabola

if a> 0 then the parabola open upward (vertex is a minimum)

if a< 0 then the parabola open downward (vertex is a maximum)

In this problem we have

$y=x^{2}+8x-21$

Convert to vertex form

Complete the square

$y+21=x^{2}+8x$

$y+21+16=(x^{2}+8x+16)$

$y+37=(x^{2}+8x+16)$

$y+37=(x+4)^{2}$

$y=(x+4)^{2}-37$ --------> equation in vertex form

The vertex is the point $(-4,-37)$

the parabola open upward (vertex is a minimum)

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A is correct the y intercept is (0,5)

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Can someone help me out. Paying big points

Ksenya-84 [330]

Answer:

1) the quadrants go counter clockwise, Quadrant I is the upper right square, Quadrant II is the upper left square, Quadrant III is the lower left square, and Quadrant IV is the lower right square.

2) Quadrant II

3) Quadrant IV

4) Quadrant III

5) Quadrant I

6) Both would be on the horizontal axis

7) Both would be on the vertical axis

Step-by-step explanation:

Hope this helped!

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Answer:

your answer would be 1kg

Step-by-step explanation:

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