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joja [24]
3 years ago
14

Mrs. Benjamin analyzed the scores her 24 students earned on their most recent vocabulary test. The results showed a mean score o

f 76 (out of 100), a median score of 80, and a range of 38. Select ALL the statements that can be supported by the data.
A. The lowest score earned by any student was a 38.
B. 50% of the students earned a score of 80 or higher.
C. 25% of the students earned a score of 80 or lower.
D. The highest score earned by any student was a 76.
E. The highest score was 38 points greater than the lower score.
Mathematics
1 answer:
tekilochka [14]3 years ago
3 0
Here are all the possible statements we can gather:

B. 50% of the students earned a score of 80 or higher. 
E. The highest score was 38 points greater than the lower score. (Since range is defined as the difference between the highest number and the lowest number)

Hope my answer has helped.
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The lengths (in inches) of a sample of snakes in the Clarmont Zoo's reptile house are as follows: 9, 15, 86, 13, 16, 101, 85, 10
elena-14-01-66 [18.8K]

Answer:

A higher value of standard deviation tells us that there is high variability in the length of the snake from the mean length of the snake.

Step-by-step explanation:

We are given the following information in the question:

Sample of snakes in the Clarmont Zoo's reptile house are as follows:

9, 15, 86, 13, 16, 101, 85, 10, 14, 16, 102

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{467}{11} = 42.4545

Sum of squares of differences = 1119.206611 + 753.7520659 + 1896.206612 + 867.5702477 + 699.842975 + 3427.570248 + 1810.115703 + 1053.29752 + 809.6611568 + 699.842975 + 3545.661158 = 16682.72727

S.D = \sqrt{\frac{16682.72727}{10}} = 40.8445

Standard deviation:

  • Standard deviation tells you how spread out the data is.
  • It is a measure of how far each observed value is from the mean.
  • A low standard deviation indicates that the values tend to be close to the mean, while a high standard deviation indicates that the values are spread out over a wider range.

A higher value of standard deviation tells us that there is high variability in the length of the snake from the mean length of the snake. The data is overspread over a wide range.

6 0
3 years ago
Eliminate the parameter for the following set of parametric equations: x= t^2 + 2 y= 4t^2
mr_godi [17]

Answer:

Solution : y = 4x - 8

Step-by-step explanation:

The first thing we want to do is isolate t², rather than t. Why? As you can see when we substitute t² into the second equation, it will be easier than substituting t, as t is present in the form t². So, let's isolate t² in the first equation --- ( 1 )

x = t² + 2,

t² = x - 2

Now let's substitute this value of t² in the second equation --- ( 2 )

y = 4t²,

y = 4(x - 2),

y = 4x - 8 ~ And hence our solution is option c.

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Step-by-step explanation:

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