Given the expression,

We will have to rationalize the denominator first. To rationalize the denominator we have to multiply the numerator and denominator both by the square root part of the denominator.
![[(8x-56x^2)(\sqrt{14x-2})]/[(\sqrt{14x-2})(\sqrt{14x-2})]](https://tex.z-dn.net/?f=%20%5B%288x-56x%5E2%29%28%5Csqrt%7B14x-2%7D%29%5D%2F%5B%28%5Csqrt%7B14x-2%7D%29%28%5Csqrt%7B14x-2%7D%29%5D%20)
If we have
, we will get
by multiplying them. And
.
So here in the problem, we will get,
![[(8x-56x^2)(\sqrt{14x-2})]/(14x-2)](https://tex.z-dn.net/?f=%20%5B%288x-56x%5E2%29%28%5Csqrt%7B14x-2%7D%29%5D%2F%2814x-2%29%20)
Now in the numerator we have
. We can check 8x is common there. we will take out -8x from it, we will get,


And in the denominator we have
. We can check 2 is common there. If we take out 2 from it we will get,

So we can write the expression as
![[(-8x)(7x-1)(\sqrt{14x-2})]/[2(7x-1)]](https://tex.z-dn.net/?f=%20%5B%28-8x%29%287x-1%29%28%5Csqrt%7B14x-2%7D%29%5D%2F%5B2%287x-1%29%5D%20)
is common to the numerator and denominator both, if we cancel it we will get,

We can divide -8 by the denominator, as -8 os divisible by 2. By dividing them we will get,


So we have got the required answer here.
The correct option is the last one.
On January 31, Jean Marie’s business receives a bill for that month’s utilities in the amount of $500. Jean sets it aside because she does not plan to pay the bill until its due date of February 15. What effect, if any, does this event have on the company’s accounting equation as of January 31?
Solution: The event that Jean does not plan to pay the bill until due date of February 15 must be recorded. Recording this event would increase the liabilities and decrease equity on January 31.
Answer:
<span>y=<span><span><span>log<span>(x)</span></span>−<span>log<span>(50000)</span></span></span><span>log<span>(0.8)</span></span></span></span>
Explanation:
write as : <span>y=50000<span><span>(0.8)</span>x</span></span>
Taking logs:
<span><span>log<span>(y)</span></span>=<span>log<span>(50000)</span></span>+<span>log<span>(.<span><span>(0.8)</span>x</span>.)</span></span></span>
But <span>log<span>(.<span><span>(0.8)</span>x</span>.)</span></span> is the same as <span>x<span>log<span>(0.8)</span></span></span>
Thus
<span>x=<span><span><span>log<span>(y)</span></span>−<span>log<span>(50000)</span></span></span><span>log<span>(0.8<span>)
</span></span></span></span></span>Now swap the x'x and the y's giving:<span><span><span><span><span>
</span></span></span></span></span>
<span>y=<span><span><span>log<span>(x)</span></span>−<span>log<span>(50000)</span></span></span><span>log<span>(0.8<span>)
my teacher helped a little bit
</span></span></span></span></span>
Ln(56) = 4x-9
ln(56) + 9 = 4x
(ln(56) + 9)/4 = x
Answer: y=1/3x - 22/3
Step-by-step explanation: