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goldfiish [28.3K]
3 years ago
11

I WILL GIVE BRAINLY!! HELP!! ASAP!! Links WILL be reported... thank you.

Mathematics
1 answer:
marissa [1.9K]3 years ago
3 0

Answer:

my answer would be c. y=lX+7l

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butalik [34]

Answer:

cxa=t cause you are mulltipling to find the total cost

7 0
3 years ago
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I need to put parenthesis in order to make this statement true.....help
saveliy_v [14]

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Step-by-step explanation:

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3 years ago
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Find an explicit formula for the following sequence, an which starts with a1=2/3. 2/3,3/4,4/5,5/6,…
Flura [38]

Answer:

Step-by-step explanation:

a1=2/3

sequence is 2/3,3/4,4/5,...

for numerator a1=2

d=3-2=1

numerator of nth term=a1+(n-1)d=2+(n-1)×1=2+n-1=n+1

denominator = 1 more than numerator=n+1+1=n+2

so an=(n+1)/(n+2)

or for denominator a1=3,d=4-3=1

denominator of nth term=3+(n-1)×1=3+n-1=n+2

an=(n+1)/(n+2)

6 0
3 years ago
Is .07 closer to 1/2,0 or 1
Nikitich [7]
0, because 1/2 = 0.50. therefore .07 is more closer to 0
7 0
3 years ago
AYUDA CON ESTO!!! ALGUIEN PORFAVOR
Gre4nikov [31]

Answer:

Problem 1)  frequency:  160 heartbeats per minute, period= 0.00625 minutes (or 0.375 seconds)

Problem 2) Runner B has the smallest period

Problem 3) The sound propagates faster via a solid than via air, then the sound of the train will arrive faster via the rails.

Step-by-step explanation:

The frequency of the football player is 160 heartbeats per minute.

The period is (using the equation you showed above):

Period = \frac{1}{frequency} = \frac{1}{160} \,minutes= 0.00625\,\,minutes = 0.375\,\,seconds

second problem:

Runner A does 200 loops in 60 minutes so his frequency is:

\frac{200}{60} = \frac{10}{3} \approx  3.33   loops per minute

then the period is: 0.3 minutes (does one loop in 0.3 minutes)

the other runner does 200 loops in 65 minutes, so his frequency is:

\frac{200}{65} = \frac{40}{13} \approx  3.08   loops per minute

then the period is:

\frac{13}{40} =0.325\,\,\,minutes

Therefore runner B has the smaller period

8 0
3 years ago
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