Answer:
k=2
Step-by-step explanation:
Clearly both the functions are straight lines
the equation of straight line passing through the two points (a , b) and (c , d) is 
Now f(x) passes through (-4 , 0) and (0 , 4)
the equation is 
y=x+4
Now g(x) passes through (-2 , 0) and (0 , 4)
the equation is 
y=2x+4
here f(x)=x+4 and g(x)=2x+4
clearly g(x)=f(2x)
therefore k=2
You are indeed correct good job!
Answer: (e-5)^2
Step-by-step explanation:
The box method is a good way to solve this, but for a quick explanation, start by finding a single value that when added gets -10 and when multiplied gets +25. We can find that this term is -5. We the can situate -5 into (e-5)^2 equation, where if you FOIL, you will be back at the unfactored equation. Hope this helps
Class limits are the smallest and the largest data value that can go into a class.
Class marks are the midpoints of the classes. They are obtained by averaging the limits.
Cutpoints are<span> specified values used to sort continuous variables into discrete categories.
</span><span>Class Midpoint is the middle value of each data class.
For qualitative data, </span>c<span>utpoints and midpoints make sense, but class limits and marks do not, since qualitative data cannot be grouped using Limit grouping.
option D.
</span>
Answer:
SQUARE 1:
100% ; 75%
Step-by-step explanation:
SQUARE 1:
If each square represents a whole ; the percentage of a whole = 100%
Dividing the square into 4 equal parts :
Percentage of each part :
100% ÷ 4 = 25%
Percentage represented by the shaded part:
(Percentage of each shaded part * number of shaded part)
(25% * 4) = 100%
SQUARE 2:
each square represents a whole ; the percentage of a whole = 100%
Dividing the square into 4 equal parts :
Percentage of each part :
100% ÷ 4 = 25%
Percentage represented by the shaded part:
(Percentage of each shaded part * number of shaded part)
(25% * 3) = 75%
