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Step2247 [10]
4 years ago
9

Given the equation 2x − 5 = 8, which order of operations completely solves for x?

Mathematics
1 answer:
blagie [28]4 years ago
4 0

2x - 5 = 8      Add 5 on both sides

2x - 5 + 5 = 8 + 5

2x = 13          Divide 2 on both sides to get "x" by itself

x = \frac{13}{2}


So addition and division

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Q(a+1) - 2q(a) if q(x) = x²+3x+4​
siniylev [52]

q(x) =  {x}^{2} + 3x + 4

_________________________________

Step(1)

To find q(a) we just need to put a instead of x in q(x) function.

Let's do it...

q(a) =  {a}^{2} + 3a + 4

Multiply sides by -2 :

- 2q(a) =  - 2( {a}^{2} + 3a + 4)

- 2q(a) =  - 2 {a}^{2} - 6a - 8

_________________________________

Step (2)

To find q(a+1) we just need to put a+1 instead of x in q(x) function.

Let's do it...

q(a + 1) =  ({a + 1})^{2} + 3(a + 1) + 4 \\

q(a + 1) =  {a}^{2} + 2a + 1 + 3a + 3 + 4 \\

q(a + 1) =  {a}^{2} + 5a + 8

_________________________________

Step (3)

q(a + 1) - 2q(a) =

{a}^{2} + 5a + 8 - 2 {a}^{2} - 6a - 8 =  \\

-  {a}^{2} - a  =  - a(a + 1)

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

8 0
4 years ago
B. Create an equation and sketch a graph that:
aev [14]

Answer:

Step-by-step explanation:

Yes.

3 0
2 years ago
Read 2 more answers
ONLY THE BRAINLIEST OF USERS ANSWER THIS QUESTION 30 POINTS!!!!!!!!!!!!!!!
denis23 [38]

Answer:

8*5^n-1 / 2^n-1 = n

This is the function for your sequence


3 0
3 years ago
Read 2 more answers
Help please with this question
choli [55]

Answer:

They lose about 2.79% in purchasing power.

Step-by-step explanation:

Whenever you're dealing with purchasing power and inflation, you need to carefully define what the reference is for any changes you might be talking about. Here, we take <em>purchasing power at the beginning of the year</em> as the reference. Since we don't know when the 6% year occurred relative to the year in which the saving balance was $200,000, we choose to deal primarily with percentages, rather than dollar amounts.

Each day, the account value is multiplied by (1 + 0.03/365), so at the end of the year the value is multiplied by about

... (1 +0.03/365)^365 ≈ 1.03045326

Something that had a cost of 1 at the beginning of the year will have a cost of 1.06 at the end of the year. A savings account value of 1 at the beginning of the year would purchase one whole item. At the end of the year, the value of the savings account will purchase ...

... 1.03045326 / 1.06 ≈ 0.9721 . . . items

That is, the loss of purchasing power is about ...

... 1 - 0.9721 = 2.79%

_____

If the account value is $200,000 at the beginning of the year in question, then the purchasing power <em>normalized to what it was at the beginning of the year</em> is now $194,425.14, about $5,574.85 less.

7 0
3 years ago
Which of the following polynomials have like terms?
Artyom0805 [142]
It should be 37y4+6y^2-2y^2+y-1
4 0
3 years ago
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