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Lemur [1.5K]
3 years ago
5

Complete this statement 27x^4a^2+18x^2a^3=9x^2a^2 ( )

Mathematics
1 answer:
gtnhenbr [62]3 years ago
6 0
<span>27x</span>⁴<span>a</span>²<span>+18x</span>²<span>a</span>³<span>=9x</span>²<span>a</span>²(3x²+2a)
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-6x -(3x)= what's the answer to this please help me .
sleet_krkn [62]

-6x -(3x)

Pretend that there is a -1 in front of the bracket

-6x-1(3x)

mutiply the bracket by -1

(-1)(3x)= -3x

-6x-3x= -9x

Answer: -9x

3 0
3 years ago
Read 2 more answers
Plz help i need a answer asap!!!
omeli [17]

Answer:

c.) 31

Step-by-step explanation:

comment if u need explanation :))

8 0
2 years ago
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Filipo is building a rectangular sandbox . The length of the sandbox is 1 foot longer than twice the width of the sandbox .the p
Alla [95]

Answer:

Part A : D.) 2w + 2(2w+ 1) = 29

Part B : Length of the sandbox is 10 feet.

Step-by-step explanation:

Given,

Perimeter = 29 ft

We need to find the equation for the perimeter and also the length of the sandbox.

Solution,

Let the width of the sandbox be 'w'.

Now as per question said;

The length of the sandbox is 1 foot longer than twice the width of the sandbox.

So we can say that;

Length = 2w+1

Now we know that the perimeter is equal to the sum of twice of length and width.

framing in equation form, we get;

Perimeter = 2(2w+1)+2w

we have given the perimeter, so on substituting the value, we get;

29=2(2w+1)+2w

Hence The equation used to find the width is  29=2(2w+1)+2w.

Now we solve for 'w'.

Applying distributive property, we get;

4w+2+2w=29\\\\6w+2=29

Subtracting both side by '2' we get

6w+2-2=29-2\\\\6w=27

Dividing both side by 6 we get;

\frac{6w}{6}=\frac{27}{6}\\\\w=4.5\ ft

Width of the sandbox = 4.5 ft

Length of the sandbox = 2w+1=2\times4.5 +1 = 9+1=10\ ft

Hence Length of the sandbox is 10 feet.

3 0
3 years ago
In a list of five consecutive odd integers, the sum of the first and double the last is 139. What is the largest sum?
Leviafan [203]

Answer: 49

Step-by-step explanation:

From your question, I think you mean the largest number. The answer is given below.

Let the five consecutive odd numbers be:

a, a+2, a+4, a+6 and a+8.

Thee sum of the first and double the last is 139. This can be written as:

a + 2(a+8) = 139

a + 2a + 16 = 139

3a + 16 = 139

3a = 139 - 16

3a = 123

a = 123/3

a = 41

The first number = 41

The largest number = a+8 = 41 + 8 = 49.

7 0
3 years ago
What is 40 multiplied by 10
andreev551 [17]

400 id your answer.

Thanks for the points

6 0
3 years ago
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