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3 years ago

Does anyone know the answer to this? Algebra 2

Mathematics

1 answer:

natulia [17]3 years ago

3 0

Answer:

Step-by-step explanation:

Sinθ = $\frac{\text{Opposite side}}{\text{Hypotenuse}}$

If, sinθ = - $\frac{1}{2}$ and π < θ < $\frac{3\pi }{2}$

Since, sinθ is negative, angle θ will be in IIIrd quadrant.

And the measure of angle θ will be (180° + 30°)

θ = 210°

It's necessary to remember that tangent and cotangent of angle θ in quadrant III are positive.

Therefore, cos(210°) = $-\frac{\sqrt{3} }{2}$

tan(210°) = $\frac{1}{\sqrt{3} }$

csc(210°) = $-\frac{1}{2}$

sec(210°) = $-\frac{2}{\sqrt{3} }$

cot(210°) = √3

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Find the lengths of each side. Label with numbers. WILL GIVE BRAINLIEST

choli [55]

Answer:

2 x + 6 . 8 = 8 x + I . 4

8x _2x = 6.8 - 1.4

6x = 5.4

X= 0.9

2x+ 6-8= 2×0.9 + 6.8 =8.6

5 0

3 years ago

a plane flies 5.0km due north from a point O and then 6.0km on a bearing of 060° the pilot then changes course on a bearing of 1

Virty [35]

The plane flies a distance of approximately 10.536 kilometers in straight line and with a bearing of approximately 035°.

A plane that travels a distance $r$ , in kilometers, with a bearing of $\theta$ sexagesimal degrees can be represented in standard position by means of the following expression:

$\vec r = r\cdot (\sin\theta, \cos \theta)$ (1)

We can obtain the resulting vector ( $\vec R$ ) by the principle of superposition:

$\vec R = \Sigma_{i=1}^{n} [r_{i}\cdot (\sin \theta_{i}, \cos \theta_{i})]$ (2)

If we know that $r_{1} = 5\,km$ , $\theta_{1} = 0^{\circ}$ , $r_{2} = 6\,km$ , $\theta_{2} = 60^{\circ}$ , $r_{3} = 4\,km$ and $\theta_{3} = 120^{\circ}$ , then the resulting vector is:

$\vec R = 5\cdot (\sin 0^{\circ}, \cos 0^{\circ}) + 6\cdot (\sin 60^{\circ}, \cos 60^{\circ}) + 4\cdot (\sin 120^{\circ}, \cos 120^{\circ})$

$\vec R = (5\sqrt{3}, 6) \,[km]$

The magnitude of the resultant is found by Pythagorean theorem:

$\|\vec R\| = \sqrt{R_{x}^{2}+R_{y}^{2}}$

And the bearing is determined by the following inverse trigonometric relationship:

$\theta_{R} = \tan^{-1} \left(\frac{R_{y}}{R_{x}}\right)$ (3)

If we know that $R_{x} = 5\sqrt{3}\,km$ and $R_{y} = 6\,km$ , then the magnitude and the bearing of the resultant is:

$\|\vec R\| = \sqrt{(5\sqrt{3})^{2}+6^{2}}$

$\|\vec R\| \approx 10.536\,km$

$\theta_{R} = \tan^{-1} \left(\frac{6}{5\sqrt{3}} \right)$

$\theta_{R} \approx 34.715^{\circ}$

The plane flies a distance of approximately 10.536 kilometers in straight line and with a bearing of approximately 035°.

To learn more on vectors, we kindly invite to check this verified question: brainly.com/question/21925479

6 0

3 years ago

Spencer goes on a 5 hour work shift. After

romanna [79]

Answer:

18/5 hours or 3 3/5 hours

Step-by-step explanation:

I assume the break is at 7/5 hours.

5 hours - 7/5 hours = 25/5 hours - 7/5 hours = 18/5 hours = 3 3/5 hours

5 0

3 years ago

Which pair of angles are vertical angles?

Irina-Kira [14]

Answer:

Option 4.∠ERT and ∠MRC

Step-by-step explanation:

Definition of vertical angles : The angles opposite each other when two lines cross. They are always equal.Vertical" refers to the vertex (where they cross).They are also called vertically opposite angles.

Option 1. ∠KRC and ∠CRH

Refer the figure .

These angles does not satisfy the definition of vertical angles . since these angles are not opposite.

Option 2. ∠KRE and ∠ERT

These angles does not satisfy the definition of vertical angles . since these angles are not opposite.

Option 3. ∠MRC and ∠KRM

These angles does not satisfy the definition of vertical angles . since these angles are not opposite.

Option 4.∠ERT and ∠MRC

MT and EC are the two lines that cross each other at vertex R ,

Thus ∠ERT and ∠MRC are opposite to each other .

Hence ∠ERT and ∠MRC are pair of vertcal angles .

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3 years ago

Read 2 more answers

Find the sum of the geometric sequence. 1, 1/2, 1/4, 1/8, 1/16

dezoksy [38]

I would convert them all to the denominator 16, due to the smallest fraction and all of them can be converted to it.

1 = 16/16
1/2 = 8/16
1/4 = 4/16
1/8 = 2/16
1/16 = 1/16

1+ 2 + 4 + 8 + 16 = 31

31/16 = 1 15/16

Hope this helps!

7 0

3 years ago

Read 2 more answers