<span>Answer:
Roma Sherry drove 330 miles from her hometown to Tucson. During her return trip, she was able to increase her speed by 11 mph. If her return trip took 1 hour less time, find her original speed and her speed returning home.
:
Let s = original speed
then
(s+11) = return speed
:
Write a time equation: Time = distance%2Fspeed
:
Original time = return time + 1 hr
330%2Fs = 330%2F%28%28s%2B11%29%29 + 1
:
Multiply equation by s(s+11) and you have:
330(s+11) = 330s + s(s+11)
:
330s + 3630 = 330s + s^2 + 11s
:
0 = 330s - 330s + s^2 + 11s - 3630
:
A quadratic equation:
s^2 + 11s - 3630 = 0
Factor this to:
(s + 66)(s - 55) = 0
Positive solution
s = 55 mph is original speed.
:
Find the time
330/55 = 6 hr, original time
and
330/66 = 5 hrs, faster time; confirms our solution.</span>
Answer:
i. The horizontal component of the ball = 15.8
ii. The vertical component of the ball = 11.2
Step-by-step explanation:
A thrown ball is an example of a projectile, whose motion can be explained with respect to both horizontal and vertical components.
Horizontal component of the ball = U Cos θ
Vertical component of the ball = U Sin θ
where U is the initial velocity of the ball, and θ is the angle of projection.
Thus for the given question,
U = 70 km/hr (19.44 m/s)
θ = 35°
So that;
i. The horizontal component of the ball = 19.44 Cos 35°
= 19.44 x 0.8192
= 15.785
The horizontal component of the ball = 15.8.
ii. The vertical component of the ball = 19.44 Sin 35°
= 19.44 x 0.5736
= 11.151
The vertical component of the ball = 11.2
The answer is :
.0085470085
Hope This Helps!!
:)
