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4 years ago

How do I do this question it is really hard

Mathematics

1 answer:

gulaghasi [49]4 years ago

6 0

Answer:

Step-by-step explanation:

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4|a| + 8 -a, if a = -2<br><br> PLEASE HELP!!!!!!!!!!!!!! I'm stuck on this!!

r-ruslan [8.4K]

4|a| + 8 - a, if a = -2

What we're doing here is plugging in the given value of a for every instance of a in the expression.

4|-2| + 8 - (-2)

---The absolute value of a number is its distance from 0. -2 is 2 units away from 0, so the absolute value of -2 is 2. And, remember two negatives make a positive!

4(2) + 8 + 2

8 + 8 + 2

16 + 2

Hope this helps!

3 0

2 years ago

The area of a rectangular rug is 25.5 square meters. The width of the rug is 3.75 meters. Found the length of the rug by dividin

Grace [21]

6.8 because 25.5/3.75 = 6.8

8 0

3 years ago

Read 2 more answers

What two numbers multiply to equal 50 and add up to equal -15

Tanzania [10]

The two numbers are 5,10. Which is multiply to equal 50 and add up to equal 15.

Step-by-step explanation:

Step:1

Let, X,Y.

Where X, Y are two numbers.

Step:2

Form the Multiplication equation from given,

X×Y=50 (∵ Multiply to equal 50)

Step:3

Form Addition equation from given,

X+Y= 15 (∵ Add equal to 15)

Step:4

Check for alternatives to satisfy both equations

Assume, X=1, Y=14

1+14=15 (Satisfy addition equation)

1×14=14 (Not satisfy multiplication equation)

Assume, X=2, Y=13

2+13=15 (Satisfy addition equation)

2×13=26 (Not satisfy multiplication equation)

similarly.,

assume X=5, Y=10

5+10=15 (Satisfy addition equation)

5×10=50 (Satisfy multiplication equation)

So, the two numbers are 5,10.

7 0

4 years ago

Create a matrix that is equal to F+G. The first matrix below is named F and the second matrix below is named G. Name the new mat

likoan [24]

F+G:

$F+G=\begin{bmatrix}{-1.8} & {-8.6} & {} \\ {2.85} & {-1.4} & {} \\ {-1.8} & {5.1} & {}\end{bmatrix}+\begin{bmatrix}{1.32} & {-1.9} & {} \\ {2.25} & {0.0} & {} \\ {-6.2} & {1.4} & {}\end{bmatrix}$

Then, add the elements that occupy the same position: