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3 years ago

I need help with this question please

Mathematics

1 answer:

Novay_Z [31]3 years ago

4 0

I think the answer is 80 because I’m point 2 it’s is 40 and in point 3 is 60 and in point 5 is 100 so I am guessing each goes by 20 so what is between 60 and 100 if you can’t by 20s would be 80 I don’t know if I am correct tho

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Question 5 of 10

Harman [31]

Answer:

Step-by-step explanation:

6x + c = k ( isolate the term in x by subtracting c from both sides )

6x = k - c ( isolate x by dividing both sides by 6 )

x = $\frac{k-c}{6}$

5 0

1 year ago

70. Write the standard form of the equation of the line with

nasty-shy [4]

Answer:

y = -2x - 8

Step-by-step explanation:

<u>Use the point slope form: (y - y1) = m(x - x1)</u>

(y - (-4)) = -2(x - (-2))

y + 4 = -2(x + 2)

y + 4 - 4 = -2x - 4 - 4

y = -2x - 8

Answer: y = -2x - 8

6 0

3 years ago

Read 2 more answers

Condense the following logs into a single log:

mamaluj [8]

QUESTION 1

The given logarithm is

$8\log_g(x)+5\log_g(y)$

We apply the power rule of logarithms; $n\log_a(m)=\log_(m^n)$

$=\log_g(x^8)+\log_g(y^5)$

We now apply the product rule of logarithm;

$\log_a(m)+\log_a(n)=\log_a(mn)$

$=\log_g(x^8y^5)$

QUESTION 2

The given logarithm is

$8\log_5(x)+\frac{3}{4}\log_5(y)-5\log_5(z)$

We apply the power rule of logarithm to get;

$=\log_5(x^8)+\log_5(y^{\frac{3}{4}})-\log_5(z^5)$

We apply the product to obtain;

$=\log_5(x^8\times y^{\frac{3}{4}})-\log_5(z^5)$

We apply the quotient rule; $\log_a(m)-\log_a(n)=\log_a(\frac{m}{n} )$

$=\log_5(\frac{x^8\times y^{\frac{3}{4}}}{z^5})$

$=\log_5(\frac{x^8 \sqrt[4]{y^3} }{z^5})$

7 0

2 years ago

3(x+10)=2(2x+16) help please & thank you

andrew-mc [135]

In this question, you have to isolate <em>x</em>.

First, use the distributive property.

$3x+30=4x+32$

Now that you have distributed, subtract the constants.

7 0

3 years ago

Which pair of polygons is similar

DedPeter [7]

I didn’t see an image or anything but I looked it up and it said regular polygons, since they have the sides all the same length they must always be in the same proportions, and their interior angles are always the same.

6 0

2 years ago