Answer:
The amount invested at 9% is $93000
The amount invested at 10% is $303000
Step-by-step explanation:
Let the amount invested at 9% interest rate be x
And the amount invested at 10% rate be y
Simple Interest from x in a year = 0.09x
Simple Interest from y in a year = 0.1y
But y = 24000 + 3x
And the sun of the interests, 0.09x + 0.1y = 38670
Now we have a simultaneous eqn
y = 24000 + 3x (eqn 1)
0.09x + 0.1y = 38670 (eqn)
Substitute y into eqn 2
0.09x + 0.1(24000 + 3x) = 38670
0.09x + 2400 + 0.3x = 38670
0.39x = 38670 - 2400
x = 36270/0.39 = $93000
y = 24000 + 3x = 24000 + 3 × 93000 = $303000
Answer:
See attached
Step-by-step explanation:
Given function:
Table and graph are attached
Zeros are included in the graph
<u>Zero's are obtained:</u>
x = 0 ⇒ y = 8
y = 0 ⇒ Solving quadratic equation
- -2x² + 5x + 8 = 0
- x = (-5 ± √(25 + 2*4*8))/-4
- x = 3.608
- x = -1.108
So zeros are (0, 8), (3.608, 0) and (-1.108, 0)
1.
<span>1.5x-1 > 6.5
1.5x>1+6.5
</span>1.5x>7.5, divide by 1.5
x>5, is represented by the region to the right of the vertical line x=5
2.
<span>7x+3 < -25
7x<-25-3
7x<-28, divide by 4:
x<-4
</span>x<-4, is represented by the region to the left of the vertical line x=-4
Answer: check the picture
For this case we must resolve the following expression:
We have to:

The base change rule can be used if a and b are greater than 1 and are not equal to x.
We substitute the values in the base change formula, using 

Answer:
-4
Option A
47.5 mph- because 30+65 equals 95 and 95 divided by 2 is 47.5