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lesantik [10]
3 years ago
15

Help me u guys i really neeed help.

Mathematics
2 answers:
Ivenika [448]3 years ago
4 0

Answer:

The letter is     Q

And the quadrant is (x,-y) i.e quadrant no. 4

Step-by-step explanation:

Sonja [21]3 years ago
3 0

Answer:

Q, quadrant 4

Step-by-step explanation:

You might be interested in
Which of the relations given by the following sets of ordered pairs is a function?
solniwko [45]

Answer:

B

Step-by-step explanation:

You can solve this by using the vertical line test. When you do the vertical line test, the vertical line should only pass through one point on the function. That means that there can to be only one value of x for every y. Set B is the only set where the x value doesn't repeat.

8 0
4 years ago
• karger's min cut algorithm in the class has probability at least 2/n2 of returning a min-cut. how many times do you have to re
MrRissso [65]
The Karger's algorithm relates to graph theory where G=(V,E)  is an undirected graph with |E| edges and |V| vertices.  The objective is to find the minimum number of cuts in edges in order to separate G into two disjoint graphs.  The algorithm is randomized and will, in some cases, give the minimum number of cuts.  The more number of trials, the higher probability that the minimum number of cuts will be obtained.

The Karger's algorithm will succeed in finding the minimum cut if every edge contraction does not involve any of the edge set C of the minimum cut.

The probability of success, i.e. obtaining the minimum cut, can be shown to be ≥ 2/(n(n-1))=1/C(n,2),  which roughly equals 2/n^2 given in the question.Given: EACH randomized trial using the Karger's algorithm has a success rate of P(success,1) ≥ 2/n^2.

This means that the probability of failure is P(F,1) ≤ (1-2/n^2) for each single trial.

We need to estimate the number of trials, t, such that the probability that all t trials fail is less than 1/n.

Using the multiplication rule in probability theory, this can be expressed as
P(F,t)= (1-2/n^2)^t < 1/n 

We will use a tool derived from calculus that 
Lim (1-1/x)^x as x->infinity = 1/e, and
(1-1/x)^x < 1/e   for x finite.  

Setting t=(1/2)n^2 trials, we have
P(F,n^2) = (1-2/n^2)^((1/2)n^2) < 1/e

Finally, if we set t=(1/2)n^2*log(n), [log(n) is log_e(n)]

P(F,(1/2)n^2*log(n))
= (P(F,(1/2)n^2))^log(n) 
< (1/e)^log(n)
= 1/(e^log(n))
= 1/n

Therefore, the minimum number of trials, t, such that P(F,t)< 1/n is t=(1/2)(n^2)*log(n)    [note: log(n) is natural log]
4 0
4 years ago
Can someone help me with this? i'll award brainiest :D
Burka [1]

Answer:

About 79 boys i think

Step-by-step explanation:

:)

6 0
3 years ago
In the diagram below, ΔPQR ≅ ΔSTR. Complete the statement ∠PRQ ≅ ___ A. ∠SRT B. ∠RST C. ∠STR D. ∠T
Oduvanchick [21]

The complete statement is ∠PRQ ≅ <u>∠SRT</u>. The correction option is A. ∠SRT

<h3>Similar triangles </h3>

From the question, we are to complete the given statement

From the given information,

We have that ΔPQR ≅ ΔSTR

This means ΔPQR is congruent to ΔSTR

Then,

∠PQR ≅ ∠STR

∠PRQ ≅ ∠SRT

∠QPR ≅ ∠TSR  

Hence, the complete statement is ∠PRQ ≅ <u>∠SRT</u>. The correction option is A. ∠SRT

Learn more on Congruent Triangles here: brainly.com/question/28032367

#SPJ1

4 0
2 years ago
18=x/3+6<br> A) 4<br> B)12<br> C)36<br> D)3
Vesna [10]

Answer:

36

Step-by-step explanation:

Flip your eq. x/3 + 6 = 18.

Solve (Number on one, variable on other)

+6 -6 = 0. 18-6=12.

Multiply.

12 * 3 = 36.

7 0
4 years ago
Read 2 more answers
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