If a neutral object loses 1.5x106 electrons, then what will be its charge? ... Felect = (9x109 N/m2/C2)•(4.65 x 10-6 C)•(7.28 x 10-6 C)/(0.658 m)2 = 0.704 N.

Step-by-step explanation:

5 0

2 years ago

I put $500 in a saving account that earns 6% interest compounded semi-annually. How much interest will be in the account after 2

Nuetrik [128]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$500\\
r=rate\to 6\%\to \frac{6}{100}\to &0.06\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2\\
t=years\to &2
\end{cases}
\\\\\\
A=500\left(1+\frac{0.06}{2}\right)^{2\cdot 2}\implies A=500(1.03)^4\implies A=562.754405$

now, "A" is the accumulated amount, including the earned interest, how much interest was it earned? well, is just A - P.

3 0

3 years ago