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Dima020 [189]
3 years ago
7

Points showing equivalent relics on the coordinate planeten

Mathematics
1 answer:
koban [17]3 years ago
3 0

Answer:

<em>Answer: (8,12) Third option</em>

Step-by-step explanation:

<u>Equivalent Ratios</u>

Nardia plotted some points showing equivalent ratios. The points shown in the graph are: (2,3), (4,6), (10,15)

The ratios of the points in the form y:x are:

\frac{3}{2}

\frac{6}{4}=\frac{3}{2}

\frac{15}{10}=\frac{3}{2}

Note all the ratios are equivalent.

From the ordered pairs provided in the choices, only one of them has the same ratio y:x.

Point (12,8) has a ratio:

\frac{12}{8}=\frac{3}{2}

Answer: (8,12) Third option

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4 years ago
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damaskus [11]
(10x + 4) + (5x-4) ≈ 180

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4 years ago
Assume that X is Normal with mean $ 240 and standard deviation $60 . the probability that , in a randomly selected week , Dan wi
enyata [817]

Answer:

The probability of Dan making less than $255 is 0.5987 or 59.87%

Step-by-step explanation:

Given that:

Mean = μ = $240

SD = σ = $60

We have to find the probability that Dan will make less than $255

First of all, we have to find the z-score of 255

z-score is denoted by z and is given by the formula

z = \frac{x-mean}{SD}

Here,

x = 255

Putting the values

z = \frac{255-240}{60}\\z = \frac{15}{60}\\z = 0.25

Now we have to look at the z-score table to find the probability of 0.25

P(x<255) = 0.5987

Converting into percentage

59.87%

Hence,

The probability of Dan making less than $255 is 0.5987 or 59.87%

3 0
3 years ago
Find the distance from the point to the line. (-1,-2,1);x=4+4t, y=3+t, z=6-t .The distance is ____ Typn exact answer, using radi
lawyer [7]

Answer:

The distance is<u>  4.726 </u>

Step-by-step explanation:

we need to find the distance from the point to the line

Given:- point (-1,-2,1) and line ; x=4+4t, y=3+t, z=6-t .

used formula d=\frac{|a\times b|}{|a|}

Let point P be (-1,-2,1)

using value t=0 and t=1

The point Q (4 , 3, 6) and R ( 8, 4, 5)

Let a be the vector from Q to R :   a = < 8 - 4, 4 - 3, 5 - 6 > = < 4, 1, -1 >

Let b be the vector from Q to P:    b = < -1 - 4, -2 - 3, 1 - 6> = < -5, -5, -5 >

The cross product of a and b is:

a \times b= \begin{vmatrix} i & j & k\\ 4 &1&-1\\-5 &-5&-5\\ \end{vmatrix}

= -6i+15j-15k

The distance is : d=\frac{\sqrt{(-6)^{2}+(15)^{2}+(-15)^{2}}}{\sqrt{(4)^{2}+(1)^{2}+(-1)^{2}}}

=\frac{\sqrt{36+225+225}}{\sqrt{16+1+1}}

=\frac{\sqrt{36+225+225}}{\sqrt{16+1+1}}

d=\frac{\sqrt{486}}{\sqrt{18}}

≈4.726

Therefore, the distance is<u>  4.726 </u>

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3 years ago
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V125BC [204]

Answer:

5.17

Step-by-step explanation:

just at 10 pecent

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Read 2 more answers
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