Answer:
E. 800%
Step-by-step explanation:
Since,
u = 8d/h² __________ eqn (1)
Now, density (d) is doubled and usage (h) is halved.
Hence the new life (u'), becomes:
u' = 8(2d)/(0.5h)²
u' = 8(8d/h²)
using eqn (1), we get:
u' = 8u
In percentage,
u' = 800% of u
In words, the percentage increase in useful life of the equipment is <u>800%</u>.
3x+4y=12
4y = - 3x + 12
y = -3/4 x + 3; This line has slope equal - 3/4
Perpendicular lines, slope is opposite and reciprocal so slope of new line = 4/3
Passing point (6 , -2)
y + 2 = 4/3(x - 6)
y + 2 = 4/3 x - 8
y = 4/3 x - 10
Answer
Equation: y = 4/3 x - 10
Disbeylover us right, the answer is n÷11. I hope this helps
Answer:
see the attachment
7 hours
Step-by-step explanation:
The cost for River Y is a constant (not dependent upon hours), so is c = 41.
The cost for River Z is the sum of the deposit and the hourly cost, so is ...
c = 13+4n
These equations and their graphs are shown in the attachment. The graphs cross where n=7, indicating you have to rent a canoe for 7 hours for the cost to be the same on both rivers.
