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3 years ago

5

If you help me on this god bless you, I NEED HELP !

1 answer:

joja [24]3 years ago

4 0

Answer:

given
additive property of equality
segment addition postulate
segment addition postulate
transitive property

Step-by-step explanation:

In an equation, the additive property of equality states that if we add or subtract the same number to both sides of an equation, the sides remain equal.

transitive property, If a = b and b = c, then a = c.

Segment Addition Postulate Defined. The segment addition postulate states that if we are given two points on a line segment, A and C, a third point B lies on the line segment AC if and only if the distances between the points meet the requirements of the equation AB + BC = AC.

I hope this was good enough for you:

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Answer:

b is 15.

Step-by-step explanation:

Trust me on this, The answer could only be 15 when solving for b. Hopefully that helps.

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Law Incorporation [45]

<u>Answer-</u>

<em>The line equation is,</em>

$\boxed{\boxed{6x+15y-10=0}}$

<u>Solution-</u>

The line $y =3x-5$ meets x-axis at the point M, i.e M is the x-intercept of this line. At the x-intercept y=0, so

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So, coordinate of M is $(\dfrac{5}{3},\ 0)$

The line $3y+2x=2$ meets y-axis at point N, i.e N is the y-intercept of this line. At the y-intercept x=0, so

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So, coordinate of N is $(0,\ \dfrac{2}{3})$

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$\Rightarrow \dfrac{y-y_1}{y_2-y_1}=\dfrac{x-x_1}{x_2-x_1}$

$\Rightarrow \dfrac{y-0}{\frac{2}{3}-0}=\dfrac{x-\frac{5}{3}}{0-\frac{5}{3}}$

$\Rightarrow \dfrac{y}{\frac{2}{3}}=\dfrac{x-\frac{5}{3}}{-\frac{5}{3}}$

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$\Rightarrow -5y=2x-\dfrac{10}{3}$

$\Rightarrow 2x+5y-\dfrac{10}{3}=0$

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$\Rightarrow 6x+15y-10=0$

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