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chubhunter [2.5K]
3 years ago
6

Bettween 09 00 and 10 30, a man walks a distance of 27 km. What is his average speed in km/h?

Mathematics
1 answer:
Nataly [62]3 years ago
7 0

Answer:

18

Step-by-step explanation:

9 to 10:30  = 1.5 hour

27/1.5= 18

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Rosemary walks each week for exercise. Let d represent the distance walked and h represent the number of hours spent walking.
nadya68 [22]
Ok last week she walked 18/6 which equals 3 and 3 is less than 2.5. 2.5h is really just that times how many hours.D is the amount of miles.So,the awnser is going to  be b or d.But we dont know what d is in d=2,5h so we have to asume that b is the awnser
8 0
3 years ago
Read 2 more answers
Clarita is a single taxpayer with two dependent children, ages 10 and 12. Clarita
lidiya [134]

Step-by-step explanation:

1. Clarita's total income =

Adjusted gross income (all from wages)  + standard  deduction

= $19,600  +  $3,000 = $22,600  ( Actual spending is only $3,000 for two children)

According to USA (Pub.503.,)

you exclude or deduct dependent care benefits provided by a dependent care benefit plan, the total amount you exclude or deduct must be less than the dollar limit for qualifying expenses (generally, $3,000 if one qualifying person was cared for or $6,000 if two or more qualifying persons were cared for). (If two or more qualifying persons were cared for, the amount you exclude or deduct will always be less than the dollar limit because the total amount you can exclude or deduct is limited to $5,000.

2.Child and dependent care  credit for 2019 is Zero

Because .,According to Income tax rules in USA (pub 501) "the deductions for personal and dependency exemptions for tax years 2018 through 2025 are suspended, and therefore, the amount of the deduction is zero. But in determining whether you may claim a person as a qualifying relative for 2019, the person's gross income must be less than $4,200, not zero."

Here Clarita's gross income is $22,600 ., more than $4,200

5 0
3 years ago
What is the length<br> of HJ expressed in terms of pie?
frutty [35]

im not sure but pie is 3.14

6 0
3 years ago
a survey amony freshman at a certain university revealed that the number of hours spent studying the week before final exams was
Marat540 [252]

Answer:

Probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

Step-by-step explanation:

We are given that the number of hours spent studying the week before final exams was normally distributed with mean 25 and standard deviation 15.

A sample of 36 students was selected.

<em>Let </em>\bar X<em> = sample average time spent studying</em>

The z-score probability distribution for sample mean is given by;

          Z = \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }  ~ N(0,1)

where, \mu = population mean hours spent studying = 25 hours

            \sigma = standard deviation = 15 hours

            n = sample of students = 36

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the average time spent studying for the sample was between 29 and 30 hours studying is given by = P(29 hours < \bar X < 30 hours)

    P(29 hours < \bar X < 30 hours) = P(\bar X < 30 hours) - P(\bar X \leq 29 hours)

      

    P(\bar X < 30 hours) = P( \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} } < \frac{ 30-25}{\frac{15}{\sqrt{36} } }} } ) = P(Z < 2) = 0.97725

    P(\bar X \leq 29 hours) = P( \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} } \leq \frac{ 29-25}{\frac{15}{\sqrt{36} } }} } ) = P(Z \leq 1.60) = 0.94520

                                                                    

<em>So, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2 and x = 1.60 in the z table which has an area of 0.97725 and 0.94520 respectively.</em>

Therefore, P(29 hours < \bar X < 30 hours) = 0.97725 - 0.94520 = 0.0321

Hence, the probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

7 0
3 years ago
Given: AB ∥ DC , m CB =62°, m∠DAB=104° Find: m∠DEA, m∠ADB
Snowcat [4.5K]

Answer:

Step-by-step explanation:

sum of angles of parallelogram=360 degrees

adjacent angles add up to 180 degrees (supplementary angles)

Angle A=104 (DAB=104)

Angle D=180-104=76 degrees (angle ADB)

Angle B=60 degrees

Angle C=180-60=120 (DCB)    

4 0
3 years ago
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