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Galina-37 [17]
2 years ago
5

U2+10u+21 factor this plz i dont know how

Mathematics
1 answer:
Lady_Fox [76]2 years ago
8 0
(u - 3) • (u - 7) I believe
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const2013 [10]

Answer: B

Step-by-step explanation: The line crosses the Y axis at 3

3 0
3 years ago
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<img src="https://tex.z-dn.net/?f=%20-%205%20%5Csqrt%7B49%20-%208a%20%3D%20%20-%2035%7D%20" id="TexFormula1" title=" - 5 \sqrt{4
Tcecarenko [31]

- 5 \sqrt{49 - 8a =  - 35}  \\  \\ 1. \:  - 8a = 0 \\  \\ 2. \:  \frac{ - 8a}{ - 8} =  \frac{0}{ - 8}   \\ a = 0

7 0
3 years ago
The mean incubation time of fertilized eggs is 21 days. Suppose the incubation times are approximately normally distributed with
Korvikt [17]

Answer:

a) 20.16; b) 20.49 and 21.51

Step-by-step explanation:

We use z scores for each of these.  The formula for a z score is

z=\frac{X-\mu}{\sigma}.

For part a, we want the 20th percentile; this means we want 20% of the data to be lower than this. We find the value in the cells of the z table that are the closest to 0.20 as we can get; this is 0.2005, which corresponds with a z score of -0.84.

Using this, 21 as the mean and 1 as the standard deviation,

-0.84 = (X-21)/1

-0.84 = X-21

Add 21 to each side:

-0.84+21 = X-21+21

20.16 = X

For part b, we want the middle 39%.  This means we want 39/2 = 19.5% above the mean and 19.5% below the mean; this means we want

50-19.5 = 30.5% = 0.305 and

50+19.5 = 69.5% = 0.695.

Looking these values up in the cells of the z table, we find those exact values; 0.305 corresponds with z = -0.51 and 0.695 corresponds with z = 0.51:

-0.51 = (X-21)/1

-0.51 = X-21

Add 21 to each side:

-0.51+21 = X-21+21

20.49 = X

0.51 = (X-21)/1

0.51 = X-21

Add 21 to each side:

0.51+21 = X-21+21

21.51 = X

4 0
3 years ago
What is the area of 4 10 20
Gnoma [55]
Just multiply the base times height times width which would give you 800
5 0
3 years ago
7. Sapna travelled 48 km to meet her parents. She travelled the first 18 km by car and the remaining distance by train. Find the
Anton [14]

The fraction of the journey Sapna traveled by car and train is 3/8 and 5/8 respectively.

We know that fraction is an expression in mathematics used to denote the division of two whole numbers.

Given that the total distance = 48 km.

The distance Sapna traveled by car = 18 km.

So, the fraction is = distance traveled by car/total distance = 18/48 = 3/8

The distance Sapna traveled by train = 48 - 18 km = 30 km.

So, the fraction is = distance traveled by train/total distance = 30/48 = 5/8

Therefore the fraction of the journey Sapna traveled by car and train is 3/8 and 5/8 respectively.

Know more about fractions here -

brainly.com/question/10354322

#SPJ10

6 0
2 years ago
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