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Colt1911 [192]
3 years ago
8

Help plz it due today

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
6 0

Answer:

Point A  - 1/2 and - 1/4

Point B  - 2 1/2 and 1 1/2

Point C 1/4 and 1/2

Step-by-step explanation:

You might be interested in
Complete a prime factor tree for the number 136
cestrela7 [59]

136 is a composite number.

136 = 1 x 136,

2 x 68,

4 x 34

or 8 x 17

. Factors of 136: 1, 2, 4, 8, 17, 34, 68, 136.

Prime factorization: 136 = 2 x 2 x 2 x 17, which can also be written 136 = 2³ x 17.


5 0
3 years ago
Read 2 more answers
NEED THIS DONE ASAP PLEASE ANSWER WITH FULL WORK
Travka [436]

The function of the table is quadratic in nature and is given as follows:   y = 2x² -1

<h3>What is a quadratic function?</h3>

A quadratic function is one of the following: f(x) = ax² + bx + c, where a, b, and c are positive integers and a, b, and are not equal to zero.

Given the nature of a quadratic function (y =  ax² + bx + c) we pick three pairs of (x, y) from the table as follows:

A) (0, -1)

B) (1, 1)

C) (2, 7)

Then we say:

A) (0, -1) →   -1 = a(0)²  + b(0) + c =

-1 = c ..................................1

B) (1, 1) →   1 = a(1)² + b(1) + c =

1 = a + b + c.......................2

C) (2, 7) → 7 = a(2)² + b(2) + c

7 = a (4) + 2b + c

7 = 4a + 2b + c .................3

Using elimination and substitution, let us substitute equation 1 into equation 2;

that is

1 = a + b + (-1)

1 = a + b -1
1 + 1 = a + b

2 = a + b................................4

From the above we can also say,

b = 2 - a...................................5

substitute 5 into 3 we have

7 = 4a + 2 (2-a) + (-1)

7 = 4a + 4 - 2a  - 1

7 = 4a - 2a + 4 - 1

7 = 2a + 3

7- 3 = 2a

4 = 2a

a = 4/2

a = 2

taking [a = 2] and [c = -1], subsitute these into equation 2

1 = a + b + c

1 = 2 + b + (-1)

1 = 2 + b - 1

1 = 2 - 1 + b

1 = 1 + b

b = 1-1

b= 0

Hence,

a = 2

b = 0

c = -1

Hence:

y = 2 * x² + (0) x + (-1)

y = 2x² -1

Hence the equation for the above table is y = 2x² -1

Learn more about Quadratic Functions:
brainly.com/question/1214333

#SPJ1

8 0
1 year ago
Find three consecutive integers whose sum is 33
zhenek [66]

Answer:

10 +11 + 12

Step-by-step explanation:

We know this because 10 + 11 +12 equals 33

4 0
3 years ago
Read 2 more answers
Ally makes a rectangle with 45 square inch tiles. She arranges the tiles in 5 equal rows. How many square inch tiles are in each
Iteru [2.4K]
Ally would have to have 9 tiles in each row. You have to divide 45 divided by 5 because you have a certain amount. For the picture, Create 5 rows, and then but 9 squares for the tiles in each row. If you count out your tiles, you will get a total of 45.
3 0
4 years ago
Read 2 more answers
Pre-Calculus - Systems of Equations with 3 Variables please show work/steps
Tatiana [17]

Answer:

x = 10 , y = -7 , z = 1

Step-by-step explanation:

Solve the following system:

{x - 3 z = 7 | (equation 1)

2 x + y - 2 z = 11 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Swap equation 1 with equation 2:

{2 x + y - 2 z = 11 | (equation 1)

x + 0 y - 3 z = 7 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Subtract 1/2 × (equation 1) from equation 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y/2 - 2 z = 3/2 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Multiply equation 2 by 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Add 1/2 × (equation 1) to equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

0 x - (3 y)/2 + 8 z = 37/2 | (equation 3)

Multiply equation 3 by 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

0 x - 3 y + 16 z = 37 | (equation 3)

Swap equation 2 with equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x - y - 4 z = 3 | (equation 3)

Subtract 1/3 × (equation 2) from equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x+0 y - (28 z)/3 = (-28)/3 | (equation 3)

Multiply equation 3 by -3/28:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract 16 × (equation 3) from equation 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y+0 z = 21 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 2 by -3:

{2 x + y - 2 z = 11 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 2 from equation 1:

{2 x + 0 y - 2 z = 18 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Add 2 × (equation 3) to equation 1:

{2 x+0 y+0 z = 20 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 1 by 2:

{x+0 y+0 z = 10 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Collect results:

Answer: {x = 10 , y = -7 , z = 1

3 0
3 years ago
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