Help plz it due today

The base of a triangle is 3 cm and the height is 5 cm. What mathematical operation(s) described must be performed in order to fi

Firdavs [7]

Answer:

C.

Step-by-step explanation:

To find the area of a triangle, one must multiply the base by the height then divide by 2.

So, the area of this triangle would be 7.5

6 0

3 years ago

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9 m 11 m 16 m 4 m Find the area of this figure.

coldgirl [10]

Answer:

Can u send picture with it pls so i can figure it out?

What are the two shapes

Step-by-step explanation:

rectangle: length times width

triangle: base times height divided by 2

parallelgram: Base times height

square: side times side

*If you get it right then follow me on roblox: Supertasticgg

and sub to Flamingo

ANd almost forgot trapezoid: base 1 + base 2 times by height then divide with 2

6 0

3 years ago

Hree people play a game in which one person loses and two people win each round. The loser must pay each winner the amount that

ipn [44]

Answer:

$7 ; $4 ; $3

Step-by-step explanation:

Given that:

1 player loses and 2 wins

Loser pays each winner amount each winner already has

3 rounds was played

At the end, each player has lost 1 round each and has $8.00

Since each player lost 1 round each, then each player won twice.

Given that the players are A, B and C

Starting from the last round :

Recall; they all have $8 after the last round.

If A lost the last round and pays B and C the amount they already have.

B and C finally have $8, Hence amount A paid B and C = 8/2 = $4 each

Hence, at the end of 2nd round / before last round :

A has ($8 paid + $8 final) = $16

B and C each have $4

End of first round before 2nd round of game:

If B lost, and pays A and C the amount they already have ;

A finally has 16 hence, amount B pays A = 16/2 = $8

Amount B pays C = 4/2 = $2

A = $8

B = $4 + $(8 + 2) = $14

C = $2

Ist round

C will lose :

Amount C pays B = $14 / 2 = $7

Amount C pays A = $8 /2 = $4

Hence, amount C has before round 1:

$7 + $4 + $2 = $13

Hence; Before the game ;

Either of the three players have ;

$7 ; $4 and $13

6 0

3 years ago

Social Sciences Alcohol Abstinence The Harvard School of Public Health completed a study on alcohol consumption on college campu

Scilla [17]

Answer:

a) There is a 6.69% probability that a randomly selected female student abstains from alcohol.

b) If a randomly selected female student abstains from alcohol, there is a 82.87% probability that she attends a coeducational college.

Step-by-step explanation:

This is a probability problem:

We have these following probabilities:

-20.7% of a woman attending an all-women college abstaining from alcohol.

-6% of a woman attending a coeducational college abstaining from alcohol.

-4.7% of a woman attending an all-women college

- 100%-4.7% = 95.3% of a woman attending a coeducational college.

(a) What is the probability that a randomly selected female student abstains from alcohol?

$P = P_{1} + P_{2}$

$P_{1}$ is the probability of a woman attending an all-women college being chosen and abstaining from alcohol. There is a 0.047 probability of a woman attending an all-women college being chosen and a 0.207 probability that she abstain from alcohol. So:

$P_{1} = 0.047*0.207 = 0.009729$

$P_{2}$ is the probability of a woman attending a coeducational college being chosen and abstaining from alcohol. There is a 0.953 probability of a woman attending a coeducational college being chosen and a 0.06 probability that she abstain from alcohol. So:

$P_{2} = 0.953*0.06 = 0.05718$

So, the probability of a randomly selected female student abstaining from alcohol is:

$P = P_{1} + P_{2} = 0.009729 + 0.05718 = 0.0669$

There is a 6.69% probability that a randomly selected female student abstains from alcohol.

(b) If a randomly selected female student abstains from alcohol, what is the probability she attends a coedücational colege?

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

Here:

What is the probability of a woman attending a coeducational college, knowing that she abstains from alcohol.

It can be calculated by the following formula:

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

We have the following probabilities:

$P(B)$ is the probability of a woman from a coeducational college being chosen. So $P(B) = 0.953$

$P(A/B)$ is the probability of a woman abstaining from alcohol, given that she attends a coeducational college. So $P(A/B) = 0.06$

$P(A)$ is the probability of a woman abstaining from alcohol. From a), $P(A) = 0.0669$

So, the probability that a randomly selected female student attends a coeducational college, given that she abstains from alcohol is:

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{(0.953)*(0.06)}{(0.0669)} = 0.8287$

If a randomly selected female student abstains from alcohol, there is a 82.87% probability that she attends a coeducational college.

4 0

3 years ago

An article reports "attendance dropped 2% this year, to 3750." What was the attendance before the drop?

Anastasy [175]

Answer:

7,500 was the attendance before the drop.

Step-by-step explanation:

3750 x 2

5 0

2 years ago

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