The situation can be modeled by a geometric sequence with an initial term of 284. The student population will be 104% of the prior year, so the common ratio is 1.04.
Let \displaystyle PP be the student population and \displaystyle nn be the number of years after 2013. Using the explicit formula for a geometric sequence we get
{P}_{n} =284\cdot {1.04}^{n}P
n
=284⋅1.04
n
We can find the number of years since 2013 by subtracting.
\displaystyle 2020 - 2013=72020−2013=7
We are looking for the population after 7 years. We can substitute 7 for \displaystyle nn to estimate the population in 2020.
\displaystyle {P}_{7}=284\cdot {1.04}^{7}\approx 374P
7
=284⋅1.04
7
≈374
The student population will be about 374 in 2020.
The answer is 100 degrees.
Answer:
He would pay a total of $21.50
Step-by-step explanation:
A trick that I learned is to take the zeros and decimals off. Then multiply. Ex) 75 × 2 =150. Take away the zero (15) and ad the decimal (1.5)
I'm not the best at explaining but I hope this helps
6x² - 5x + -21 = 0
Because this whole equation equals zero, we must simply factorize the first half of the equation, or the left side.
(3x - 7)(2x + 3) = 0
I was never really taught a specific way to factorize, so I usually just guess and check when factorizing. It usually takes a long time, it always gives you the tight answer.
Then, take each equation and make it equal zero.
3x - 7 = 0 AND 2x + 3 = 0
3x - 7 = 0
Add 7 to both sides.
3x = 7
Divide both sides by 3.
x = 7/3
Now, we do our second equation.
2x + 3 = 0
Subtract 3 from both sides.
2x = -3
Divide both sides by 2.
x = -3/2
So, x = 7/3 AND x = -3/2
So, your answer is C) x = 7/3, x = -3/2
~Hope I helped!~
