All categories

3 years ago

Help please, 100 points

Mathematics

2 answers:

Nina [5.8K]3 years ago

8 0

Answer:

Less than 5

Step-by-step explanation:

o-na [289]3 years ago

7 0

9514 1404 393

Answer:

less than -5

Step-by-step explanation:

The open circle indicates that -5 is not part of the solution set. This means the inequality will not include "or equal to."

The arrow pointing to the left indicates values less than -5 are in the solution set.

p < -5

You might be interested in

If f(x)=6x-15 and f(a)=30, what is the value of a?<br> Please help

mariarad [96]

Answer:

$a=7.5$

Step-by-step explanation:

Given the function $f(x)=6x-15$ and the output $30$ when $x=a$ , we can write the equation:

$6a-15=30$

$6a=45$

$a=7.5$

We can insert the value of $a$ into the function to verify the output equals $30$ :

$f(a) = 6a-15$

$= 6(7.5)-15$

$=30$

∴ We have verified that $a=7.5$

Hope this helps :)

7 0

3 years ago

Idk how to answer this question

Naya [18.7K]

Answer:

It's z^11

Step-by-step explanation:

To multiply exponents with the same base (z), you add the exponents so in this case you add 5 and 6 to get z^11

5 0

4 years ago

Read 2 more answers

Exposure to microbial products, especially endotoxin, may have an impact on vulnerability to allergic diseases. The following ar

Softa [21]

Answer:

A. E ( U ) = 21.5454 , E ( F ) = 8.39333

B. M ( U ) = 17.0 , M ( F ) = 18.0

C. E ( U' ) = 17.0 , E ( F' ) = 7.95384

D. T ( U ) = 9.091% , T ( F ) = 6.667%

Step-by-step explanation:

Solution:-

- Two sample sets ( U ) and ( F ) that define the concentration ( EU/mg ) of endotoxin found in urban and farm homes as follows:

U: 6.0 5.0 11.0 33.0 4.0 5.0 80.0 18.0 35.0 17.0 23.0

F: 2.0 15.0 12.0 8.0 8.0 7.0 6.0 19.0 3.0 9.8 22.0 9.6 2.0 2.0 0.5

- To determine the mean of a sample E ( U ) or E ( F ) the following formula from descriptive statistics is used:

$E ( X ) = Sum ( X_i ) / n$

Where,

Xi : Data iteration

n: Sample size

Therefore,

$E ( U ) = \frac{Sum (U_i )}{n_u} \\\\E ( U ) = \frac{6.0 + 5.0 + 11.0 + 33.0 + 4.0+ 5.0 +80.0+ 18.0+ 35.0+ 17.0+ 23.0 }{11} \\\\E ( U ) = 21.54545\\\\E ( F ) = \frac{Sum (F_i )}{n_f} \\\\E ( F ) = \frac{2.0 + 15.0 + 12.0 + 8.0 + 8.0 + 7.0 + 6.0 + 19.0+ 3.0+ 9.8+ 22.0+ 9.6+ 2.0+ 2.0+ 0.5 }{15} \\\\E ( F ) = 8.39333$

- To determine the sample median we need to arrange the data for both samples ( U ) and ( F ) in ascending order as follows:

U: 4.0 5.0 5.0 6.0 11.0 17.0 18.0 23.0 33.0 35.0 80.0

F: 0.5 2.0 2.0 2.0 3.0 6.0 7.0 8.0 8.0 9.6 9.8 12.0 15.0 19.0 22.0

- Now find the mid value for both sets:

Median term ( U ) = ( n + 1 ) / 2

= ( 11 + 1 ) / 2 = 12/2 = 6th term

Median ( U ), 6th term = 17.0

Median term ( F ) = ( n + 1 ) / 2

= ( 15 + 1 ) / 2 = 16/2 = 8th term

Median ( F ), 8th term = 8.0

- We will now trim the smallest and largest observation from each set.

- In set ( U ) we see that smallest data corresponds to ( 4.0 ) while the largest data corresponds to ( 80.0 ). We will exclude these two terms and the trimmed set is defined as:

U': 5.0 5.0 6.0 11.0 17.0 18.0 23.0 33.0 35.0

- In set ( F ) we see that the smallest data corresponds to ( 0.5 ) while the largest data corresponds to ( 22.0 ). We will exclude these two terms and the trimmed set is defined as:

F': 2.0 15.0 12.0 8.0 8.0 7.0 6.0 19.0 3.0 9.8 9.6 2.0 2.0

- We will again use the previous formula to calculate means of trimmed samples ( U' ) and ( F' ) as follows:

$E ( U' ) = \frac{5.0+ 5.0+ 6.0+ 11.0+ 17.0+ 18.0+ 23.0+ 33.0+ 35.0}{9} \\\\E ( U' ) = 17$

$E ( F' ) = \frac{2.0 +2.0+ 2.0 +3.0+ 6.0+ 7.0+ 8.0+ 8.0+ 9.6+ 9.8+ 12.0+ 15.0+ 19.0}{13} \\\\E ( F' ) = 7.95384$

- The trimming percentage is known as the amount of data removed from the original sample from top and bottom of sample size of 11 and 15, respectively.

- We removed the smallest and largest value from each set. Hence, a single value was removed from both top and bottom of each data set. We can express the trimming percentage for each set as follows:

$T ( U ) = \frac{1}{11} * 100 = 9.091\\\\T ( F ) = \frac{1}{15} * 100 = 6.667$ %

- The trimming pecentages for each data set are 9.091% and 6.667% respectively.

7 0

3 years ago

What is the area of a triangle whose sides are 10 meters, 14 meters, and 20 meters long? A.65 m2 b.100 m2 c. 70 m2 d.50 m2

denpristay [2]

Answer: Option A. 65 m^2

Solution:

Sides: a=10 m, b=14 m, c=20 m

Area: A=?

A=sqrt [p(p-a)(p-b)(p-c) ]

Semi-perimeter: p=(a+b+c)/2

p=(10 m+14 m+20 m)/2

p=(44 m)/2

p=22 m

A=sqrt [ (22 m)(22 m-10 m)(22 m-14 m)(22 m-20 m)]

A=sqrt [ (22 m)(12 m)(8 m)(2 m) ]

A=sqrt [ 4,224 m^4 ]

A=64.99230723 m^2

A=65 m^2

7 0

3 years ago

Read 2 more answers

Write (−1/4)⋅(−1/4)⋅(−1/4) using exponents.

Semenov [28]

Answer:

(-1/4)³

Step-by-step explanation:

(−1/4)⋅(−1/4)⋅(−1/4)

= (-1/4)³

3 0

3 years ago