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babymother [125]
3 years ago
12

Please help me with this problem​

Mathematics
1 answer:
Rom4ik [11]3 years ago
6 0

y=x^2 + x - 2

x + y = 1

Replace y in the second equation:

x + x^2 + x -2 = 1

Simplify:

x^2 + 2x -2 = 1

Subtract 1 from both sides:

x^2 + 2x -3 = 0

Factor:

(x-1) (x+3) = 0

Solve for both x's:

x = 1 and x = -3

Now replace x in the second equation and solve for y using both x values:

1 + y = 1, y = 0

-3 + y = 1, y = 4

Now you have (1,0) and (-3,4) as solutions for (x,y)

XY = x times y:

1 x 0 = 0

-3 x 4 = -12

The answer would be -12

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Answer:

B is the better detergent

Step-by-step explanation:

If A has a lower number on the 1-10 scale, that means on average it was closer to the lower end, or the least clean end. This means that A cleans worse than B., and B is better.

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3 years ago
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I need help with this please respond rn
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3 years ago
Write and then solve the differential equation for the statement: "The rate of change of y with respect to x is inversely propor
sesenic [268]
Brief review of proportionality relationships:

When two quantities a,b are \textbf{directly} proportional, that means any change in a manifests a \textbf{direct} change (think "in the same direction") in b.

Silly example: "The more I eat, the fatter I get." Here the amount one eats is directly proportional to one's body weight.

This change isn't always one-for-one, so we introduce a constant k to account for any scaling that occurs on either variables behalf. In general, though, we can write a directly proportional relationship as a=kb.

Now, when a,b are \textbf{inversely} proportional, then a change in a manifests a change in b in the \textbf{inverse} (opposite) direction.

Silly example: "The more I eat, the less thin I get."

This time we write the relation as ab=k.

To get back to your problem: To say that the rate of change of y(x) is inversely proportional to \sqrt y is to say that there is some constant k such that

\sqrt y\dfrac{\mathrm dy}{\mathrm dx}=k

This is a separable ODE:

y^{1/2}\,\mathrm dy=k\,\mathrm dx
\displaystyle\int y^{1/2}\,\mathrm dy=\int k\,\mathrm dx
\dfrac23y^{3/2}+C_y=kx+C_x
\dfrac23y^{3/2}=kx+C
y^{3/2}=\dfrac{3k}2x+C
y=\left(\dfrac{3k}2x+C\right)^{2/3}
8 0
3 years ago
I have an 86% in math, my final is worth 25% of my grade. where would i be if i failed it? ​
kobusy [5.1K]

Answer:

Depends

Step-by-step explanation:

Depends on how many questions you missed. I'm going to assume that you mean you somehow missed every question. So, 86% - 25% would be 46%.

3 0
3 years ago
Please help me answer this and learn how to find the equation for line of best fit
const2013 [10]

Answer:

y=-12/5x+62

Step-by-step explanation:

to solve this i turned two point form, 5,50 and 17 1/2,20, into slope intercept form by using the formula y-y1=(y2-y1/x2-x1)(x-x1), which when input with the data becomes y-50=(20-50/17 1/2-5)(x-5) which then becomes y-50=-12/5(x-5), then y-50=-12/5x+12, and finally y=-12/5x+62

6 0
3 years ago
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