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3 years ago

5

Obtenha os zeros da função

xFormula1" title="f(x) = 2x {}^{2} + 32" alt="f(x) = 2x {}^{2} + 32" align="absmiddle" class="latex-formula">

1 answer:

natka813 [3]3 years ago

6 0

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6x^2-9x +2=0 solve the quadratic equation using the quadratic formula

balu736 [363]

<u>ANSWER: </u>

The roots of $6 x^{2}-9 x+2=0$ are $\frac{9+\sqrt{33}}{4}, \frac{9-\sqrt{33}}{4}$

<u>SOLUTION:</u>

Given, quadratic equation is $6 x^{2}-9 x+2=0$ --- eqn (1)

We need to find the roots of given quadratic equation using quadratic formula.

Quadratic formula for general quadratic equation $a x^{2}+b x+c=0$ is $X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for eqn (1) a = 6, b= -9 and c = 2

$X=\frac{-(-9) \pm \sqrt{(-9)^{2}-4 \times6 \times 2}}{2 x 2}$

$X=\frac{9 \pm \sqrt{81-48}}{4}$

$\begin{array}{l}{X=\frac{9 \pm \sqrt{33}}{4}} \\ {X=\frac{9+\sqrt{33}}{4}, \frac{9-\sqrt{33}}{4}}\end{array}$

Hence the roots of $6 x^{2}-9 x+2=0$ are $\frac{9+\sqrt{33}}{4}, \frac{9-\sqrt{33}}{4}$

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How many prime numbers are between 1 and 100

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