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Goshia [24]
3 years ago
7

20 POINTS WILL MARK BRAINLIEST plz help me very simple

Mathematics
1 answer:
Over [174]3 years ago
3 0

Answer:

£ 2.38

Step-by-step explanation:

Cost of 2.5 kg potatoes = £ 1.40

Cost of 1 kg potatoes = \frac{1.40}{2.5}\\

Cost of 4.25 kg potatoes = \frac{1.40}{2.5}*4.25\\\\

                                         =  1.40 * 1.7

                                        = £ 2.38

                                         

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I believe the answer is 2.849 
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Between x = 2 and x = 3, which function has the smallest average rate of change?
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They both have the same rate of change
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Michael and Lindsey are saving money. Michael begins with $20 and saves $5 per week. Lindsey begins with no money, but saves $10
True [87]
Let
x----------> number of weeks
y----------> saved money

we now that

<span>Michael begins with $20 and saves $5 per week
so
y=20+5x------> equation 1

and
</span><span>Lindsey begins with no money, but saves $10 per week
</span><span>y=10x-------> equation 2

</span><span>the number of weeks it will take for Lindsey and Michael to save the same amount of money is when equation 1 is equals to equation 2
</span>
therefore
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the answer is 
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3 0
3 years ago
If a(n)=24 which recursive formula could represent the sequence below? <br> ...,24,88,664,8408,...
sesenic [268]
24= 3*2^3  
88= 11*2^3
664= 83*2^3 -> 83=11+72 = 11 + 2^3*3^2
664=2^3 (11+2^3*3^2) = 88 +(2^3*2^3*3^2) = 88 +(24^2)

8408= 1051 * 2^3 -> 1051= 83+968 -> 968 = 2^3 * 11^2
8408= 2^3 (83+2^3*11^2) = 664 +(2^3*2^3*11^2) = 664 +(88^2)

So: 
a(n) = a(n-1) + a(n-2)^2

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3 1
3 years ago
50 POINTS!!! In rectangle ABCD, AB = 6 cm, BC = 8 cm, and DE = DF. The area of triangle DEF is one-fourth the area of rectangle
aalyn [17]

Answer:

EF=4\sqrt{3}

Step-by-step explanation:

In rectangle ABCD, AB = 6, BC = 8, and DE = DF.

ΔDEF is one-fourth the area of rectangle ABCD.

We want to determine the length of EF.

First, we can find the area of the rectangle. Since the length AB and width BC measures 6 by 8, the area of the rectangle is:

A_{\text{rect}}=8(6)=48\text{ cm}^2

The area of the triangle is 1/4 of this. Therefore:

\displaystyle A_{\text{tri}}=\frac{1}{4}(48)=12\text{ cm}^2

The area of a triangle is half of its base times its height. The base and height of the triangle is DE and DF. Therefore:

\displaystyle 12=\frac{1}{2}(DE)(DF)

Since DE = DF:

24=DF^2

Thus:

DF=\sqrt{24}=\sqrt{4\cdot 6}=2\sqrt{6}=DE

Since ABCD is a rectangle, ∠D is a right angle. Then by the Pythagorean Theorem:

(DE)^2+(DF)^2=(EF)^2

Therefore:

(2\sqrt6)^2+(2\sqrt6)^2=EF^2

Square:

24+24=EF^2

Add:

EF^2=48

And finally, we can take the square root of both sides:

EF=\sqrt{48}=\sqrt{16\cdot 3}=4\sqrt{3}

6 0
3 years ago
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