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marusya05 [52]
3 years ago
6

Mario sells insurance. His goal is to sell 3 types of insurance to each family on a block. He also wants to sell more than 27 po

licies. If x is the number of families he needs to sell to, which pair of inequalities correctly represents this problem?
A.9x > 27
x>3
B. 9x < 27
x<3
C. 3x >27
x>3
D. 3x < 27
x<9
please helppp
Mathematics
1 answer:
qaws [65]3 years ago
8 0

When we <em>divide </em>both sides of the <em>inequality</em>,

3x > 27 by 3,  <em>3x(3) > 27(3)</em>

we get x > 9, as the <em>simplified form </em>of the<em> inequality.</em>

Thus, giving us the answer of:

<em>x > 9</em>

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2 years ago
Rewrite the expression using distributive property : 30x + 6
Anit [1.1K]

Answer:

This cannot be done, but it can be factored as: 6(5x + 1)

Step-by-step explanation:

This expression cannot be distributed any further.

The distributive property is used when multiplying polynomials (multiplying one or more terms by two or more terms). In which case, each term in multiplied by each of the terms in the bracket, for example: .

5(x + 2)  =  5x + 10

We can factor this expression however to go the opposite direction:

30x + 6

Since 30 and 6 are both divisible by 6, we can factor it out of each term.

Divide 30x by 6 and divide 6 by 6.

6(5x + 1)

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3 years ago
A taxi travels 25 kilometers east of an airport. Then it travels from that point to a point that is 40 kilometers west of the ai
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25km east + 25km return+  40km west + 40km return = 130km

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7 0
3 years ago
CNNBC recently reported that the mean annual cost of auto insurance is 965 dollars. Assume the standard deviation is 113 dollars
velikii [3]

Answer:

P(939.6 < X < 972.5) = 0.6469

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

CNNBC recently reported that the mean annual cost of auto insurance is 965 dollars. Assume the standard deviation is 113 dollars.

This means that \mu = 965, \sigma = 113

Sample of 57:

This means that n = 57, s = \frac{113}{\sqrt{57}} = 14.97

Find the probability that a single randomly selected policy has a mean value between 939.6 and 972.5 dollars.

This is the pvalue of Z when X = 972.5 subtracted by the pvalue of Z when X = 939.6. So

X = 972.5

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{972.5 - 965}{14.97}

Z = 0.5

Z = 0.5 has a pvalue of 0.6915

X = 939.6

Z = \frac{X - \mu}{s}

Z = \frac{939.6 - 965}{14.97}

Z = -1.7

Z = -1.7 has a pvalue of 0.0446

0.6915 - 0.0446 = 0.6469

So

P(939.6 < X < 972.5) = 0.6469

3 0
2 years ago
Someone please help!! I’ll give brainliest:))
Allisa [31]
I’ve attached my work...
Hope it helps! Have a nice day :)

8 0
3 years ago
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