Answer:
![-\frac{3\sqrt[3]{t} }{2}](https://tex.z-dn.net/?f=-%5Cfrac%7B3%5Csqrt%5B3%5D%7Bt%7D%20%7D%7B2%7D)
Step-by-step explanation:
1: Write g(t) as y, resulting in 
2: Interchange the variables y and t, resulting in 
3: Multiply both sides by 27, resulting in 
4: Divide both sides by -8, resulting in 
5: Find the cube root of both sides, resulting in ![\sqrt[3]{-\frac{27t}{8} }=y](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-%5Cfrac%7B27t%7D%7B8%7D%20%7D%3Dy)
6: Apply a radical rule, resulting in ![-\sqrt[3]{\frac{27t}{8} } =y](https://tex.z-dn.net/?f=-%5Csqrt%5B3%5D%7B%5Cfrac%7B27t%7D%7B8%7D%20%7D%20%3Dy)
7: Apply another radical rule, resulting in ![-\frac{\sqrt[3]{27t} }{\sqrt[3]{8} } =y](https://tex.z-dn.net/?f=-%5Cfrac%7B%5Csqrt%5B3%5D%7B27t%7D%20%7D%7B%5Csqrt%5B3%5D%7B8%7D%20%7D%20%3Dy)
8: Simplify the denominator, resulting in ![-\frac{\sqrt[3]{27t} }{2} =y](https://tex.z-dn.net/?f=-%5Cfrac%7B%5Csqrt%5B3%5D%7B27t%7D%20%7D%7B2%7D%20%3Dy)
9: Apply yet another radical rule, resulting in ![-\frac{\sqrt[3]{27}\sqrt[3]{t} }{2} =y](https://tex.z-dn.net/?f=-%5Cfrac%7B%5Csqrt%5B3%5D%7B27%7D%5Csqrt%5B3%5D%7Bt%7D%20%20%20%7D%7B2%7D%20%3Dy)
10: Simplify ![\sqrt[3]{27}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%7D)
, resulting in ![-\frac{3\sqrt[3]{t} }{2} =y](https://tex.z-dn.net/?f=-%5Cfrac%7B3%5Csqrt%5B3%5D%7Bt%7D%20%20%20%7D%7B2%7D%20%3Dy)
Answer:
27.8 Celsius
Step-by-step explanation:
The equation to convert Fahrenheit and Celsius is:
F = (9/5)C + 32
82 = (9/5)C + 32 -- subtract 32 from both sides
50 = (9/5)C -- multiply both sides by 5
250 = 9C -- divide by 9
27.777 = C
round up to 27.8 C
Answer:
(–5, 5)
Step-by-step explanation:
Start with the x-axis (left and right).
-5 so you go to the left by 5 steps.
Next is y-axis (up and down).
Without moving your spot in -5, you move up by 5 steps.
That is point F.
Tip: (x-axis, y-axis) or (left/right, up/down)
Negative number: Left or Down
Positive number: Right or Up
Hello there!
Your final answer would be
(<span>
(6x + 5) • (6x - 5)).Your correct answer would be
(option d).I hope this helps you!</span>
