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artcher [175]
3 years ago
12

Point p lies on the directed line segment from A (2,3) to B (8,0) and portions the segment in the ratio 2 to 1

Mathematics
1 answer:
Arturiano [62]3 years ago
6 0

Answer:

The x-coordinate of point P is 6

Step-by-step explanation:

we have

A (2,3) and B (8,0)

we know that

Point P portions the segment AB in the ratio 2 to 1

so

AP=\frac{2}{3} AB

and

AP_x=\frac{2}{3} AB_x

where

AP_x represent the distance between the points A and P in the x-coordinates

AB_x represent the distance between the points A and B in the x-coordinates

AB_x=8-2=6\ units

AP_x=\frac{2}{3} (6)=4\ units

The x-coordinate of P is equal to

P_x=A_x+AP_x

where

A_x represent the x-coordinate of A

substitute the values

P_x=2+4=6

therefore

The x-coordinate of point P is 6

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A rumor spreads through a small town. Let y ( t ) be the fraction of the population that has heard the rumor at time t and assum
Ivan

Answer:

Differential equation

\frac{dy}{dt} =ky(1-y)

Solution

y=\frac{1}{1+4e^{-0.327t}}

Value of constant k=0.327 days^(-1)

The rumor reaches 80% at 8.48 days.

Step-by-step explanation:

We know

y(t): proportion of people that heard the rumor

y'(t)=ky(1-y), rate of spread of the rumor

Differential equation

\frac{dy}{dt} =ky(1-y)

Solving the differential equation

\frac{dy}{y(1-y)}=k\cdot dt \\\\\int \frac{dx}{y(1-y)} =k \int dt \\\\-ln(1-\frac{1}{y} )+C_0=kt\\\\1-\frac{1}{y} =Ce^{-kt}\\\\\frac{1}{y} =1-Ce^{-kt}\\\\y=\frac{1}{1-Ce^{-kt}}

Initial conditions:

y(0)=0.2\\y(3)=0.4\\\\y(0)=0.2=\frac{1}{1-Ce^0}\\\\1-C=1/0.2\\\\C=1-1/0.2= -4\\\\\\y(3)=0.4=\frac{1}{1+4e^{-3k}} \\\\1+4e^{-3k}=1/0.4\\\\e^{-3k}=(2.5-1)/4=0.375\\\\k=ln(0.375)/(-3)=0.327\\\\\\y=\frac{1}{1+4e^{-0.327t}}

Value of constant k=0.327 days^(-1)

At what time the rumor reaches 80%?

y(t)=0.8=\frac{1}{1+4e^{-0.327t}} \\\\1+4e^{-0.327t}=1/0.8=1.25\\\\e^{-0.327t}=(1.25-1)/4=0.0625\\\\t=ln(0.0625)/(-0.327)=8.48

The rumor reaches 80% at 8.48 days.

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