The <em>speed</em> intervals such that the mileage of the vehicle described is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h]
<h3>How to determine the range of speed associate to desired gas mileages</h3>
In this question we have a <em>quadratic</em> function of the <em>gas</em> mileage (g), in miles per gallon, in terms of the <em>vehicle</em> speed (v), in miles per hour. Based on the information given in the statement we must solve for v the following <em>quadratic</em> function:
g = 10 + 0.7 · v - 0.01 · v² (1)
An effective approach consists in using a <em>graphing</em> tool, in which a <em>horizontal</em> line (g = 20) is applied on the <em>maximum desired</em> mileage such that we can determine the <em>speed</em> intervals. The <em>speed</em> intervals such that the mileage of the vehicle is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h].
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12 times / 5 seconds * (60 seconds / 1 min) = 144 times / min
Answer:
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A greater fraction than 4/5 is 9/10
Answer:
P = 0.55 or 55 %
Step-by-step explanation:
First step: Fred has probability of 0,5 when chossing jar 1 or jar 2
Second step : The probability of chossing one chocolate chp cookie in jar 1 is 3/5 and from the jar 2 is 1/2
Then the probability of Fred to get a chocolate chip cookie is
P ( get a chocolate chip cookie ) =( 0.5 * 3/5) +( 0.5* 1/2)
P = 0.3 + 0.25
P = 0.55 or 55 %