We take each number as x = 2x 3x 4x
(2x)³+(3x)³+(4x)³=33957
8x³+27x³+64x³=33957
99x³=33957
x³=33957÷99
=∛343
x=7
2x=2×7=14
3x=3×7=21
4x=4×7=28
=the three numbers are 14,21,28
35/8 = (4 * 8 = 32) and 3 left over so answer is 4 3/8
Answer:
Assume the pair of dice are fair; if not, all bets are off!
Color one die green (G) and the other one red (R). There are 36 possibilities in throwing one green and one red die, eg (G1, R1), (G1, R2), etc; (G2, R1), (G2, R2), etc; etc; (G6, R1), (G6, R2), etc.
In the set of possible numbers from throwing a die, there are only 3 possibilities that sum to to 4: (G1, R3), (G2, R2), (G3, R1).
So the answer is 3/36, or one-twelfth.
Answer:
2/6 times
Step-by-step explanation:
only side 5 and 6 are greater than four and with fair rolls you would expect the die to land on each side once. So 2/6 times you would expect a roll greater than 4.
Answer:
x = 14
Step-by-step explanation:
10x + 160 = 300 subtract 160 from both sides
10x=140
now divide both sides by 10
x= 14