Step-by-step explanation:
JNM is a right-angled triangle with JM being the Hypotenuse.
we know JN = 20
NM = KL, and that is a side of the right-angled triangle JKL, aber we know JK and JL.
KL² = JL² - JK² = 35² - 16² = 969
KL = NM = sqrt(969) = 31.12876483...
and now,
JN² + NM² = JM²
20² + 969 = JM²
400 + 969 = JM²
1369 = JM²
JM = 37
Answer:
x = approx. 1.24 or -7.24
Step-by-step explanation:
It's hard to factor directly so we should use the quadratic formula or complete the square. I'm going to go with completing the square.
x²+6x-9=0
x²+6x=9
x²+6x is the same as x²+2·3·x, in order to make this into the algebraic identity (A+B)²=A²+2AB+B², we must add B², or in this case 3² to both sides. (A is x, B is 3)
x²+6x+9=18
(x+3)²= 18
x+3= ±√18
x= ±4.24 -3 (approximately 4.24)
First solution for x = 4.24-3 = 1.24
Second solution for x = -4.24-3 = -7.24
13x+5x=3
18x=3 divide both sides by 18
x=3/18
x=1/6
3m-3.
basically since 6 and -9 don’t have any variables, you would ignore the 3m to combine them like 6-9, which would be -3 and then adding that onto the 3m you would get 3m-3
Huh explain the question please