Answer:
The Probability that the spinner landed on the colors blue and green in any order = 2/9
Step-by-step explanation:
Given - Azul spun a tri-color spinner twice.
To find - What is the probability that the spinner landed on the colors blue and green in any order?
Solution -
Given that,
A tri-color spinner spun twice
So,
The Sample Space, S = {BB, BG, BY, GB, GG, GY, YB, YG, YY}
⇒n(S) = 9
Now,
Let A be an event that the spinner landed on the colors blue and green
So,
A = {BG, GB}
⇒n(A) = 2
Now,
Probability that the spinner landed on the colors blue and green in any order = n(A) ÷ n(S)
= 2 ÷ 9
∴ we get
The Probability that the spinner landed on the colors blue and green in any order = 2/9
The <u>correct answer</u> is:
As x→-∞, y→-3.
As x→∞, y→∞.
Explanation:
As our values of x get further into the negative numbers, the value of 2ˣ will approach 0. This is because raising a number to a negative exponent "flips" the number below the denominator and raises it to a power; we end up with smaller and smaller fractions, eventually so small that they nearly equal 0.
This will make the value of the function 0-3=-3.
As x gets larger and larger (towards ∞), the value of y, 2ˣ, continues to grow as well. Since it continues to grow exponentially, we say the value approaches ∞.
I think it is ae if i get it wrong sorry goodluck
Answer:
11.25 km h^-2
Step-by-step explanation:
Acceleration = increase in velocity / time
= 90 - 0 / 8
= 11.25 km h^-2.
Answer:
A- a regular hexagon
Step-by-step explanation:
