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3 years ago

755,082 rounded to the nearest 10,000

Mathematics

2 answers:

Tems11 [23]3 years ago

4 0

760,000 is the answer

Greeley [361]3 years ago

3 0

76,000 is rounded to the nearest 10,000

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Solve the<br> equation:<br> -X/5 =q

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Answer:

x = -5q

Step-by-step explanation:

-x/5 = q

-x = 5q

x = -5q

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3 years ago

An urn contains 5 white and 10 black balls. A fair die is rolled and that number of balls is randomly chosen from the urn. What

galina1969 [7]

Answer:

Part A:

The probability that all of the balls selected are white:

$P(A)=\frac{1}{6}(\frac{1}{3}+\frac{2}{21}+\frac{2}{91}+\frac{1}{273}+\frac{1}{3003}+0)\\ P(A)=\frac{5}{66}=0.075757576$

Part B:

The conditional probability that the die landed on 3 if all the balls selected are white:

$P(D_3|A)=\frac{\frac{2}{91}*\frac{1}{6}}{\frac{5}{66} } \\P(D_3|A)=\frac{22}{455}=0.0483516$

Step-by-step explanation:

A is the event all balls are white.

D_i is the dice outcome.

Sine the die is fair:

$P(D_i)=\frac{1}{6}$ for i∈{1,2,3,4,5,6}

In case of 10 black and 5 white balls:

$P(A|D_1)=\frac{5_{C}_1}{15_{C}_1} =\frac{5}{15}=\frac{1}{3}$

$P(A|D_2)=\frac{5_{C}_2}{15_{C}_2} =\frac{10}{105}=\frac{2}{21}$

$P(A|D_3)=\frac{5_{C}_3}{15_{C}_3} =\frac{10}{455}=\frac{2}{91}$

$P(A|D_4)=\frac{5_{C}_4}{15_{C}_4} =\frac{5}{1365}=\frac{1}{273}$

$P(A|D_5)=\frac{5_{C}_5}{15_{C}_5} =\frac{1}{3003}=\frac{1}{3003}$

$P(A|D_6)=\frac{5_{C}_6}{15_{C}_6} =0$

Part A:

The probability that all of the balls selected are white:

$P(A)=\sum^6_{i=1} P(A|D_i)P(D_i)$

$P(A)=\frac{1}{6}(\frac{1}{3}+\frac{2}{21}+\frac{2}{91}+\frac{1}{273}+\frac{1}{3003}+0)\\ P(A)=\frac{5}{66}=0.075757576$

Part B:

The conditional probability that the die landed on 3 if all the balls selected are white:

We have to find $P(D_3|A)$

The data required is calculated above:

$P(D_3|A)=\frac{P(A|D_3)P(D_3)}{P(A)}\\ P(D_3|A)=\frac{\frac{2}{91}*\frac{1}{6}}{\frac{5}{66} } \\P(D_3|A)=\frac{22}{455}=0.0483516$

7 0

2 years ago

Mr. K's math class is 1 {1}{4} hours long. After working problems on the board for 55 minutes {11}{12}hour), he gave the student

mel-nik [20]

The number of hours that students have to work on homework will be 1/3 hours.

<h3>What is subtraction?</h3>

It simply implies subtracting something from an entity, group, location, etc. Subtracting from a collection or a list of ways is known as subtraction.

Mr. K's maths class is 1 and 1/4 hours long.

After working problems on the board for 55 minutes or 11 / 12 hour.

He gave the students the rest of the class period to work on homework.

Then the number of hours that students have to work on homework will be

⇒ 1 + 1/4 - 11/12

⇒ 5 / 4 - 11/ 12

⇒ (15 - 11) / 12

⇒ 4/12

⇒ 1/3 hours

More about the subtraction link is given below.

brainly.com/question/4319655

#SPJ1

4 0

2 years ago