Question

Find the measure of the arc TDB in the circle P shown below:

Answer 1

$\huge{ \mathfrak{ \underline{ Answer \: \: ✓ }}}$

The Angle formed by an arc on the centre of the circle is double the angle made by the same arc on the circumference of the circle.

So,

$\boxed{ \mathrm{ \angle TDB = \dfrac{1}{2} \angle TPB }}$

• $\mathrm{\angle TDB = \dfrac{1}{2} \times 90 \degree}$

• $\mathrm{\angle TDB =45 \degree }$

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