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Olegator [25]
3 years ago
8

Write the equation of a line in slope intercept form given; (6,-3), (0, 5)

Mathematics
1 answer:
olganol [36]3 years ago
3 0

Answer:

y=(-4/3)x+5

Step-by-step explanation:

so you want to start by using y=mx+b

step one: find the slope (remember m is the slope in this)

m= \frac{y2-y1}{x2-x1}

m= \frac{5+3}{0-6}

m= \frac{8}{-6}

m= - \frac{4}{3\\}

step two: insert the value we found for m into the equation and take one of the given points and insert the x and y into the equation (im using (0,5)) and solve for b.

y=mx+b

5= -4/3(0)+b

5=b

step three: rewrite y=mx+b with the values we found for m and for b

y=(-4/3)x+5

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Step-by-step explanation:

The diagonals of a rhombus are perpendicular, so ∠AED = 90° and ∠BEC = 90°.

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What is the area, in square inches, of the isosceles trapezoid below?
zimovet [89]

Answer:

104.8 in^2

Step-by-step explanation:

There are 2 ways to solve this problem.

The 1st way:

Let's make 2 triangles and 1 rectangle:

Rectangle Length = 8.3

Rectangle Width = 8

So, the left out length will be 17.9 - 8.3

=> 9.6

Since, 9.6 cm is for 2 parts.

=> 9.6 / 2

=> 4.8

So, Height of the Triangle = 8

      Base of the triangle = 4.8

Area of a rectangle

=> 8.3 x 8

=> 66.4

Area of the triangle

=> 1/2 x 8 x 4.8

=> 4 x 4.8

=> 19.2

There are 2 triangles:

=> 19.2 x 2

=> 38.4

=> 66.4 + 38.4

=> 104.8

The area of the trapezoid = 104.8 in^2.

The 2nd way is:

Area of a trapezoid

=> Smaller Base + Larger Base / 2 x Height

=> 8.3 + 17.9 / 2 x 8

=> 26.2 / 2 x 8

=> 13.1 x 8

=> 104.8

The area of the trapezoid is 104.8 in^2

6 0
3 years ago
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