Answer:
8/9
Step-by-step explanation:
First we need to get both of the fractions to the same denominator.
1. 2/3 + 2/9 = 6/9 + 2/9
Next, we simply just add the fractions.
2. 6/9 + 2/9 = 8/9
The volume of the frustum is volume of the whole cone(A) minus the smaller cone(B) which is would give the volume of frustum(C) = 256cm³
<h3>Calculation of a frustum</h3>
The volume of cone A V=πr²h/3
Where radius = 20cm
The volume of cone B = V=πr²h/3
Where radius = 12cm
Therefore volume of frustum =
V=π * 20² * h/3 - π * 12² *h/3
The variables will cancel out each other
V = 20² - 12²
V = 400- 144
V = 256cm³
Therefore, the volume of the frustum(C) = 256cm³
Learn more about cone here:
brainly.com/question/1082469
#SPJ1
The total area is:
A = Ab + Al
Where,
Ab: base area
Al: lateral area
We have then:
For the base area:
Ab = (2) * (2)
Ab = 4 units ^ 2
For the lateral area:
Al = (4) * (1/2) * (2) * (root ((1) ^ 2 + (3) ^ 2))
Al = (4) * (root (1 + 9))
Al = 4raiz (10) units ^ 2
Total area:
A = 4 + 4raiz (10)
Answer:
A = 4 + 4raiz (10)
this question is incorrect because the decimal quantity functional persistent shouldnt be in a sequential farfictional order so the answer would be that satisfactory angle of theslop devided by pi and then multiplied by the persistent. hope this helped!
