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djverab [1.8K]
2 years ago
9

A rain jacket that usually costs r dollars is available at a discount. Drag and drop two

Mathematics
1 answer:
Ket [755]2 years ago
4 0

Answer: 0.81919191023020202020

Step-by-step explanation: ee

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Convert 2pi/3 to degrees
Eva8 [605]
The degree would be 120 degrees

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3 years ago
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Find the center of the circle: x2 + 2x - 3 + y2 = 5.
rosijanka [135]

Answer:

\boxed{(-1, 0)}

Step-by-step explanation:

x² + 2x - 3 + y²  = 5

Strategy:

Convert the equation to the centre-radius form:

(x - h)² + (y - k)² = r²

The centre of the circle is at (h, k) and the radius is r .

Solution:

Move the number to the right-hand side.

x² + 2x + y²  = 8

Complete the square for x

(Take half the coefficient of x, square it, and add to each side of the equation)

(x² + 2x + 1) + y² = 9

Complete the square for y

The coefficient of y is zero.

(x² + 2x + 1) + y² = 9

Express the result as the sum of squares

(x + 1)² + y² = 3²

h = -1; k = 0; r = 3

The centre of the circle is at \boxed{(-1,0)}

The graph of the circle below has its centre at (-1,0) and radius 3.

4 0
3 years ago
Solve for x. 3x+1/14=2x/8
Ludmilka [50]
It depends if it is
1. 3x+(1/14)=(2x)/8 or
2. (3x+1)/14=(2x)/8

if it is 1

1.
3x+(1/14)=2x/8
simplify 2x/8
2x/8=x/4
3x+(1/14)=x/4
find least common multiple of 14 and 4
factors of 14=2 and 7
factors of 4 are 2 and 2 so LCM=2 times 2 times 7=28
multiply both sides by 28
84x+2=7x
subtract 7x from both sides
77x+2=0
subtract 2 from both sides
77x=-2
divide both sides by 77
x=-2/77


2.
(3x+1)/14=2x/8
simpify 2x/8
2x/8=x/4
(3x+1)/14=x/4
find least common multiple of 14 and 4
factors of 14=2 and 7
factors of 4 are 2 and 2 so LCM=2 times 2 times 7=28
multiply both sides by 28
(2)(3x+1)=7x
distribute
6x+2=7x
subtract 6x from both sides
2=x

5 0
2 years ago
Order the group of quadratic functions from widest to narrowest graph<br><br> y=3x^2,y=x^2,y=2x^2
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Standard form of quadrating function ax^2 + bx + c
a > 1, the graph gets smaller as a gets bigger
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1. x^2
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If two cords are the same distance from the center of a circle than both cords are congruent 
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