Answer:
a) 3.128
b) Yes, it is an outerlier
Step-by-step explanation:
The standardized z-score for a particular sample can be determined via the following expression:
z_i = {x_i -\bar x}/{s}
Where;
\bar x = sample means
s = sample standard deviation
Given data:
the mean shipment thickness (\bar x) = 0.2731 mm
With the standardized deviation (s) = 0.000959 mm
The standardized z-score for a certain shipment with a diameter x_i= 0.2761 mm can be determined via the following previous expression
z_i = {x_i -\bar x}/{s}
z_i = {0.2761-0.2731}/{ 0.000959}
z_i = 3.128
b)
From the standardized z-score
If [z_i < 2]; it typically implies that the data is unusual
If [z_i > 2]; it means that the data value is an outerlier
However, since our z_i > 3 (I.e it is 3.128), we conclude that it is an outerlier.
You need use your strategies multiplie it than simplify to k and than move it to E tens
Answer:
3x - y = 8
y = 3x - 8
y = 3*2.5 - 8 = -0.5 --> (2.5, -0.5)
y = 3*5 - 8 = 7 --> (5, 7)
Answer C is correct.
Answer:
Find the amplitude, period, and horizontal shift. (Assume the absolute value of the horizontal shift is less than the period.)
Step-by-step explanation:
<em>BRAINLIEST?</em>
Answer:
do you
Step-by-step explanation:
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