Answer:
0.347% of the total tires will be rejected as underweight.
Step-by-step explanation:
For a standard normal distribution, (with mean 0 and standard deviation 1), the lower and upper quartiles are located at -0.67448 and +0.67448 respectively. Thus the interquartile range (IQR) is 1.34896.
And the manager decides to reject a tire as underweight if it falls more than 1.5 interquartile ranges below the lower quartile of the specified shipment of tires.
1.5 of the Interquartile range = 1.5 × 1.34896 = 2.02344
1.5 of the interquartile range below the lower quartile = (lower quartile) - (1.5 of Interquartile range) = -0.67448 - 2.02344 = -2.69792
The proportion of tires that will fall 1.5 of the interquartile range below the lower quartile = P(x < -2.69792) ≈ P(x < -2.70)
Using data from the normal distribution table
P(x < -2.70) = 0.00347 = 0.347% of the total tires will be rejected as underweight
Hope this Helps!!!
Answer:
7.5 kilograms of apples
Step-by-step explanation:
Take the total amount and subtract the amount of pears.
8.9-1.4=7.5
Let the width of the frame = x
Let the cost of a linear foot of the frame = y
Let the inside dimension of the length of the frame = a
Let the inside dimension of the width of the frame = b.
The total length of the frame = 2*a + 4x
The total width of the frame = 2b
The total amount of the frame in feet is (2a + 4x + 2b)*y = Cost
If this is incorrect please leave a message on my home page.
Answer:
AD=5.82 units
Step-by-step explanation:
tan 31=3/BD
0.6009=3/BD
BD=5
AD^2=3^2 + 5^2
AD^2=9+25=34
AD=5.82
Step-by-step explanation:
(-2/3 )x (1/6)
Cross Multiply:
.... so the 2 and 6 would become 1 and 3
..... Like that
..... (3x3=9)
-1/9 .... Answer
Hope this helps!!
