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AlexFokin [52]
3 years ago
12

A child jumps off a bridge at 75 feet, if you calculate that you will have another 10 feet going down into the water, will you s

urvive? True or False
Mathematics
1 answer:
tamaranim1 [39]3 years ago
6 0

Answer: true if I jump from their then their will no chance to back

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Answer:d=18FT

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Suppose the band sells erasers for $2 per package and pencils for $5 per package. The band sells 220 packages in all and earns a
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Let e=erasers and p=pencils. So we know the total amount of erasers plus pencils sold is equal to 220. Therefore,

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Which number line have a point that is equal to point p? Check all that apply
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Find the distance between the points E(3, 7) and F(6, 5). The exact distance between the two points is .
S_A_V [24]

Answer:

\sqrt{13}

Step-by-step explanation:

The trick here is to know the distance formula (a formula that helps you find the distance between two points).

Distance formula: distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

But now that we know this, we can simply plug in our values and solve!

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Now we can tell from our answer that the distance between both points is \sqrt{13}

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3 years ago
Calculus 2: I need help with u substitution and intergration by parts. Can someone help me understand the concept?​
snow_lady [41]

Computing an integral by substitution is the reverse of the chain rule for computing the derivative. Substitution is intended to rewrite a complicated-looking integral involving the derivative of some component expression as another much simpler integral. For example, if u=f(x), then \mathrm du=f'(x)\,\mathrm dx and

\displaystyle\int f(x)f'(x)\,\mathrm dx=\int u\,\mathrm du

###

Integration by parts is the reverse of the product rule for derivatives:

(f(x)g(x))'=f'(x)g(x)+f(x)g'(x)\implies f(x)g'(x)=(f(x)g(x))'-f'(x)g(x)

Integrating both sides with respect to x gives

\displaystyle\int f(x)g'(x)\,\mathrm dx=\int(f(x)g(x))'\,\mathrm dx-\int f'(x)g(x)\,\mathrm dx

\displaystyle\int f(x)g'(x)\,\mathrm dx=f(x)g(x)-\int f'(x)g(x)\,\mathrm dx

###

Personally, I think the best way to grasp the idea behind the two methods is to practice. You start to notice patterns to the point where knowing which is the "right" method to use becomes second nature.

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