Answer:106
Step-by-step explanation:
Let number of white marbles be w
Let number of red marbles be r
w+r = 126---------1
w = 6 +5r-----------2
Put eqn 2 in eqn 1
6+ 5r + r = 126
6 + 6r = 126
6r = 120
r = 20
w = 6 +5r =6+100
= 106
The third one, not sure about any other ones.
a > b
A . a^5b^3/ab^4 = a^4/b
B. a^4 / a*a*a*a = a^4 / a^4 = 1
C. ab^2 / a^2b = b/a
D. b*b*b/b^3 = b^3/b^3 = 1
B and D, doesn't matter what values of a and b it's always equal 1
Lets say a = 2 and b = 1
A. a^4/b = 2^4 / 1 = 16/1 = 16
C. b/a = 1/2 = 0.5
So C has the least value
Answer:
ab^2 / a^2b
Answer:
A
Step-by-step explanation:
you just have to mirror it to the other side. so K lands on (4, 1)
In order to do this we need to make them both fractions, or both decimals. It's much easier to make them both decimals, as you can get
into decimal form by simply dividing 1 by 5.
If 1/5 = .20, then 1/5 is greater than .15!
