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3 years ago

Question is in picture! Due in 30 minutes!

Chemistry

1 answer:

algol [13]3 years ago

5 0

(D)

Explanation:

Why (A), (B) and (C) don't make sense:

(A) you can't get high energies by breaking low-energy bonds. Simple law of energy conservation at work prevents it from happening.

(B) & (C) adding protons to the nucleus is not feasible due to the natural repulsion between protons. By the same token, protons cannot be removed from the nucleus by external means because of the incredibly powerful nuclear forces that bind the protons and neutrons together.

Why (D) is the correct answer:

It takes a lot of energy to hold the nucleus together. But by introducing neutrons into the nucleus, the nucleus can be rendered unstable and become radioactive. So when the nucleus breaks up, the energy that used to hold it together is now released and this energy can be harnessed to generate power.

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A 110.0 mL sample of 0.040 M Ca2+ is titrated with 0.040 M EDTA at pH 9.00. The value of logKf for the Ca2+−EDTA complex is 10.6

Alex787 [66]

Answer : The conditional formation constant is $1.83\times 10^9$

Explanation :

First we have to calculate the formation constant.

As we are given that:

$\log k_f=10.65$

$k_f=10^(10.65)$

$k_f=4.47\times 10^{10}$

Thus, the formation constant is $4.47\times 10^{10}$

Now we have to calculate the conditional formation constant.

The expression used as:

$k'_f=\alpha_y^+\times k_f$

where,

$k'_f$ = conditional formation constant = ?

$\alpha_y^+$ = activity coefficient at pH 9.00 = 0.041

$k_f$ = formation constant = $4.47\times 10^{10}$

Now put all the given values in the above expression, we get:

$k'_f=(0.041)\times (4.47\times 10^{10})$

$k'_f=1.83\times 10^9$

Therefore, the conditional formation constant is $1.83\times 10^9$

6 0

3 years ago

Of the following examples of matter, which is an amorphous solid?

DaniilM [7]

Where r the following example at

4 0

3 years ago

Read 2 more answers

What is the ph category of each of the following i need help plz

shepuryov [24]

1. base

2. neutral

3. acid

4. base

If this is what you meant, hope it helps

4 0

3 years ago

What mass of CaCl2 (in g ) should the chemist use?

solmaris [256]

The mass of the solute required is 250.25 g.

<h3>What is the mass of the solute?</h3>

We know that the number of moles of the solute can be used to obtain the mass of the solute that is required. We can now try to find the mass of the solute that is required.

Concentration of the solution = 0.350M

Volume of the solution = 6.5 L

Number of moles of the solute = 0.350M * 6.5 L

= 2.275 moles

We now have the mass of the solute as;

2.275 moles * 110 g/mol

= 250.25 g

Th measured mass of the solute that we would have to use is 250.25 g.

Learn more about solute:brainly.com/question/7932885

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Missing parts;

A chemist wants to make 6.5 L of a .350M CaCl2 solution. What mass of CaCl2(in g) should the chemist use?

3 0

1 year ago

Select the statements below that are TRUE.

vivado [14]

Answer:

I know that option F is correct

Explanation:

5 0

3 years ago