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amid [387]
3 years ago
12

4. Calculate the final concentration if water is added to 1.5 L of a 12 M

Chemistry
1 answer:
konstantin123 [22]3 years ago
6 0

Answer:

6M

Explanation:

(Molarity x Volume)concentrated soln = (Molarity x Volume)diluted doln

Molarity dilute soln = [(M x V)conc/V (dilute)] = 1.5L x 12M / 3.0L = 6M final dilute soln

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At a cost of $1600/oz, how much would you have to pay for a solid cubic foot of gold?
Alex777 [14]
<h3>You will pay $ 30876800</h3>

We'll begin by calculating the mass in ounce (oz) of a cube foot (ft³) of gold. This can be obtained as follow:

<h3 />

Density of gold = 19298 oz/ft³

Volume of gold = 1 ft³

<h3>Mass of gold =?</h3>

Density = mass /volume

19298 = mass / 1

<h3>Mass of gold = 19298 oz</h3>

Finally, we shall determine the cost of 19298 oz of gold. This can be obtained as follow:

1 oz = $ 1600

Therefore,

19298 oz = 19298 × 1600

19298 oz = $ 30876800

Therefore, a solid cube foot of gold (i.e 19298 oz) will cost $ 30876800

Learn more: brainly.com/question/15407624

4 0
2 years ago
What is the volume of 1.8 × 106 molecules He?
gavmur [86]

Answer:

Volume = 190.8

7 0
3 years ago
Read 2 more answers
Some fertilizer blends contain magnesium nitrate (MgNO3). Suppose that a chemist has 1.24 liters of a 2.13 M solution of magnesi
tamaranim1 [39]

Initial concentration of magnesium nitrate M1 = 2.13 M

Initial volume of magnesium nitrate, MgNO3  V1 = 1.24 L

Final concentration of MgNO3, M2 = 1.60 M

Let the final volume of MgNO3 upon dilution be V2

Formula to use:

M1*V1 = M2*V2

V2 = M1*V1/M2

      = 2.13 M * 1.24 L/1.60 M = 1.65 L

Thus, the final volume of magnesium nitrate solution upon dilution is 1.65 L

7 0
3 years ago
Read 2 more answers
Two or more compounds that have the same molecular formula, but different arrangements of their atoms, are called_____ isomers.
dusya [7]
Structural isomers, as the structure of the molecule is different
6 0
3 years ago
1.What is the specific heat capacity of granite when 20 kg absorbs 237 000 J of heat energy, causing its temperature to increase
Natalka [10]

<u>Given</u> :

  • Amount = 20 kg
  • Heat energy absorbed = 237,000 J
  • Temperature change = 15 °C

<u>Formula applied</u> :

\boxed {Q = mc \triangle T}

  • Q = absorbed heat
  • m = mass
  • c = specific heat capacity
  • ΔT = temperature change

Let's solve for c !

⇒ 237,000 = 20 × c × 15

⇒ c = 237,000 ÷ 300

⇒ \boxed {c = 790 J kg^{-1} K^{-1}}

∴ The specific heat capacity of granite is <u>790 J kg⁻¹ K⁻¹</u>.

5 0
1 year ago
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