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amid [387]
3 years ago
12

4. Calculate the final concentration if water is added to 1.5 L of a 12 M

Chemistry
1 answer:
konstantin123 [22]3 years ago
6 0

Answer:

6M

Explanation:

(Molarity x Volume)concentrated soln = (Molarity x Volume)diluted doln

Molarity dilute soln = [(M x V)conc/V (dilute)] = 1.5L x 12M / 3.0L = 6M final dilute soln

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How many grams of sodium sulfide can be produced when 45.3 g Na react with 105 g S?
RoseWind [281]
The chemical reaction would be as follows:

<span>2Na + S → Na2S

We are given the amount of the reactants to be used in the reaction. We use these to calculate the amount of product. We do as follows:

45.3 g Na ( 1 mol / 22.99 g ) = 1.97 mol Na
105 g S ( 1 mol / 32.06 g ) = 3.28 mol S

The limiting reactant would be Na. We calculate as follows:

1.97 mol Na ( 1 mol Na2S / 2 mol Na ) (78.04 g / mol ) = 76.87 g Na2S produced</span>
8 0
3 years ago
Which best describes a single atom of an element?
Anettt [7]

Answer:

I believe the answer is A: *It is the simplest form of matter" not 100% sure but I think that's correct

Explanation:

4 0
3 years ago
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An inference _______.
ryzh [129]

Answer:

A

Explanation:

Am Inference is an educated guess, or a guess using prior knowledge

3 0
2 years ago
The deflection of alpha particles in Rutherford’s gold foil experiments resulted in what change to the atomic model?
Strike441 [17]
Hello.

This experiment proved that atoms are not massive, they have large blanks inside the structure. Therefore, models like Thomsom's and Dalton's weren't good enough to describe the comportment of these units. A model of an atom like a <em>planetary system</em> was elaborated after this. 
5 0
3 years ago
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Phenolphthalein is an indicator that turns from colorless (acidic form) to magenta (basic form) and has a pKa of 9.40. What is t
frosja888 [35]

Answer:

40:1  is the ratio of the magenta phenolphthalein concentration to the colorless phenolphthalein concentration.

Explanation:

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

pH=pK_a+\log(\frac{[salt]}{[acid]})

pH=pK_a+\log(\frac{[magenta(Php)]}{[Php]})

We are given:

pK_a = negative logarithm of acid dissociation constant of phenolphthalein = 9.40

[magenta(Php)] = concentration of magenta phenolphthalein

[Php] = concentration of colorless phenolphthalein

pH = 11

Putting values in above equation, we get:

11=9.40+\log(\frac{[magenta(Php)]}{[Php]})

\log(\frac{[magenta(Php)]}{[Php]})=11-9.40=1.6

\frac{[magenta(Php)]}{[Php]}=10^{1.6}=39.81 :1 \approx 40:1

40:1  is the ratio of the magenta phenolphthalein concentration to the colorless phenolphthalein concentration.

7 0
3 years ago
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