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vfiekz [6]
3 years ago
10

If you needed to make 100 mL of a 0.2 M fruit drink solution from the 1.0 M fruit drink

Chemistry
1 answer:
telo118 [61]3 years ago
8 0

Answer:

We take 20.0 mL of the 1.0 M fruit drink solution and then add 80.0 mL of water to make 100 mL of a 0.2 M fruit drink solution.

Explanation:

Using the rule that: the no. of millimoles of a solution before dilution is equal to the no. of millimoles of the solution after the dilution. (MV) before dilution = (MV) after dilution. M before dilution = 1.0 M, V before dilution = ??? mL. M after dilution = 0.2 M, V after dilution = 100 mL. ∴ V before dilution = (MV) after dilution / M before dilution = (0.2 M)(100 mL) / (1.0 M) = 20.0 mL. So, we take 20.0 mL of the 1.0 M fruit drink solution and then add 80.0 mL of water to  make 100 mL of a 0.2 M fruit drink solution  

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Answer:

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Explanation:

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4 NH₃(g) + 5 O₂(g) → 4 NO (g) + 6 H₂O

By stoichiometry of the reaction, the following amounts of moles participate in the reaction:

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Then you can apply the following rule of three: if by stoichiometry 4 moles of ammonia produce 6 moles of water, 1.2 moles of ammonia will produce how many moles of water?

moles of water=\frac{1.2 moles of ammonia*6 moles of water}{4 moles of ammonia}

moles of water= 1.8 moles

<u><em>When 1.20 mole of ammonia reacts, 1.8 moles of water are produced.</em></u>

<u><em></em></u>

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