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vfiekz [6]
2 years ago
10

If you needed to make 100 mL of a 0.2 M fruit drink solution from the 1.0 M fruit drink

Chemistry
1 answer:
telo118 [61]2 years ago
8 0

Answer:

We take 20.0 mL of the 1.0 M fruit drink solution and then add 80.0 mL of water to make 100 mL of a 0.2 M fruit drink solution.

Explanation:

Using the rule that: the no. of millimoles of a solution before dilution is equal to the no. of millimoles of the solution after the dilution. (MV) before dilution = (MV) after dilution. M before dilution = 1.0 M, V before dilution = ??? mL. M after dilution = 0.2 M, V after dilution = 100 mL. ∴ V before dilution = (MV) after dilution / M before dilution = (0.2 M)(100 mL) / (1.0 M) = 20.0 mL. So, we take 20.0 mL of the 1.0 M fruit drink solution and then add 80.0 mL of water to  make 100 mL of a 0.2 M fruit drink solution  

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PLEASE HELP. !!
scoray [572]

Answer:

Potential energy = 441 N

Explanation:

Given:

Mass M = 15 kg

Height = 3 m

Find:

Potential energy

Computation:

Potential energy = mgh

Potential energy = (15)(9.8)(3)

Potential energy = 441 N

8 0
2 years ago
Given 1kg=2.20 lbs, how many kilograms are in 125 lbs?<br> (Metric conversion)
Nadya [2.5K]

Answer:

56.82 Kg

Explanation:

Given data:

1 Kg = 2.20 lbs

Number of kilogram in 125 lbs = ?

Solution:

lbs is used for pound. lb is abbreviation of libra. It is Latin word meaning balance.

Both kilogram and pounds are units of mass. Pound is smaller unit than kilogram.

one Kg = 2.20 lbs

Number of kg in 125 lbs:

125 lbs × 1 Kg/2.20 lbs

125 lbs.Kg/2.20 lbs

56.82 Kg

7 0
3 years ago
In an electric current, the ___ particles flow or are pushed along a path
MakcuM [25]
The negative particles flow or are pushed along a path
7 0
1 year ago
A biology student set up an experiment to study 9 mice. On day 1, they were measured for weight and length. Then the mice were p
Sophie [7]
The independent variable would be the variable in the research that is being manipulated by the researcher. In this case, it would be temperature in the cage as it is what is being manipulated and changed in the research design. The dependent variable would be the variable that is being studied so, for this case, it would be the length and the weight of the mice. The constants are the factors that might affect the dependent variable but is held constant or the same by the researcher throughout the experiment. These are the size of the cage, amount of food and the exercise wheel. The flaw that the scientist would be studying the length of the mice since I don't think the temperature has any effect on it. And base from he results, the change in lengths are not conclusive.
4 0
3 years ago
If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K and then I raise the pressu
mixas84 [53]

Answer:

The answer to your question is V2 = 29.6 l

Explanation:

Data

Pressure 1 = P1 = 12 atm

Volume 1 = V1 = 23 l

Temperature 1 = T1 = 200 °K

Pressure 2 = 14 atm

Volume 2 = V2 = =

Temperature 2 = T2 = 300°K

Process

1.- To solve this problem use the Combine gas law.

             P1V1/T1 = P2V2/T2

-Solve for V2

             V2 = P1V1T2 / T1P2

2.- Substitution

             V2 = (12)(23)(300) / (200)(14)

3.- Simplification

             V2 = 82800 / 2800

4.- Result

            V2 = 29.6 l

5 0
3 years ago
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