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JulijaS [17]
2 years ago
5

Would really appreciate if u could help me with all letters but even a few are great! Thanks (the graph is hard to explain so i

understand if u cant answer that lol)

Mathematics
1 answer:
defon2 years ago
8 0
Part A

The equation is b = 36*a or simply b = 36a

We take the size of the farm 'a' and multiply it by 36 to get the number of bushels of corn 'b'.

-----------------------------------

Part B

The 36 means there are 36 times more bushels of corn compared to the size of the farm in acres

For example, if the size is 2 acres then 
b = 36*a
b = 36*2
b = 72
yielding 72 bushels of corn

-----------------------------------

Part C

Along the first row you should have: 25 and 30 in the missing blanks (over 900 and 1080 respectively)

You find this by dividing the value of b over 36
eg: b/36 = 900/36 = 25

-------

Then along the bottom row you should have the following for the blanks: 0, 360, 1800

These values are found by multiplying the 'a' value by 36
eg: if a = 10 then b = 36*a = 36*10 = 360

-----------------------------------

Part D

Plot any two points you want from the table back in part C
So plot say (0,0) and (10,360). Then draw a straight line through those two points.

-----------------------------------

Part E

The point (30,1080) means a = 30 and b = 1080
So if the farm is 30 acres, then it can produce 1080 bushels of corn

Notice how
b = 36*a
b = 36*30 <<-- replace 'a' with 30
b = 180
And how this matches up with the fourth column of the table in part C. So you can use this part to get a hint of how to fill out the table (or at least know what one column looks like)


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--------------------------

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The relation as a set of ordered pairs is d. {(–2, 1), (0, -1), (2, -3)}.

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Step 1:

First, we plot the three points on the given graph.

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For the first quadrant, both x and y values are positive.

For the second quadrant, the x value is negative but the y value is positive.

For the third quadrant, both the values of x and y are negative.

For the fourth quadrant, the x value is positive but the y value is negative.

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