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snow_tiger [21]
3 years ago
7

Differentiate 2x-4x^4

Mathematics
1 answer:
MissTica3 years ago
3 0

Answer:

2-16x^3

Step-by-step explanation:

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C

Step-by-step explanation:

1/4--1/2=0.75

This is less than 2 which you get from 1/2 times 2 which =1

1+1=2

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What is the 57th term of the arithmetic sequence : 11,8,5,2
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3 years ago
Need help with 7-10 please and thank you!!
Archy [21]

Answer:

#7: MK, LS and PR

#8: PN and PQ

#9: no

#10: no

Step-by-step explanation:

#7: lines MK, LS and PR are not intersecting each other, so these lines are parallel each other

#8: between lines PN and PQ is an right angle, so the lines PN and PQ are perpendicular

#9: lines PN and KM have an intesecting point, so they're not parallel

#10: there is no right angle between lines PR and NP

3 0
3 years ago
A ball is thrown into the air with a velocity of 34 ft/s. It's height in feet after t seconds is given by y=34t-26(t)^2. Find th
kkurt [141]

Answer:

The average velocity of the ball at the given time interval is -122.3 ft/s

Step-by-step explanation:

Given;

velocity of the ball, v = 34 ft/s

height of the ball, y = 34t - 26t²

initial time, t₀ = 3 seconds

final time, t = 3 + 0.01 = 3.01 seconds

At t = 3 s

y(3) = 34(3) - 26(3)² = -132

The average velocity of the ball in ft/s is given as;

V_{avg} = \frac{y(3.01)-y(3)}{3.01 -3}\\\\V_{avg} = \frac{34(3.01)-26(3.01)^2-y(3)}{3.01 -3}\\\\V_{avg} = \frac{-133.223-y(3)}{0.01}\\\\V_{avg} = \frac{-133.223-(-132)}{0.01}\\\\V_{avg} =\frac{-1.223}{0.01}\\\\V_{avg} = -122.3 \ ft/s

Therefore, the average velocity of the ball at the given time interval is -122.3 ft/s

8 0
3 years ago
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